Please refer to the table in the dreamhome database. If the connection is successful and we run the following PHP codes on obi.kean.edu, which statement. is TRUE? 1 Cannot connect to DB\n"); 5 $query = "SELECT fname from dreamhome. Staff where sex= 'FF' and salary > 20000"; 6 $result = mysqli_query($con, $query); 7 if($result) { 8 9 10 11 if (mysqli_num_rows($result)>0) echo "Monkey\n"; else echo "Tiger\n"; 12} 13 else 14 15 16 mysqli_close($con); 17 ?> echo "Dog\n";

Please refer to the table in the dreamhome database. If the connection is successful and we run the following PHP codes on obi.kean.edu, which statement. is TRUE? 1 Cannot connect to DB\n"); 5 $query = "SELECT fname from dreamhome. Staff where sex= 'FF' and salary > 20000"; 6 $result = mysqli_query($con, $query); 7 if($result) { 8 9 10 11 if (mysqli_num_rows($result)>0) echo "Monkey\n"; else echo "Tiger\n"; 12} 13 else 14 15 16 mysqli_close($con); 17 ?> echo "Dog\n";

Oracle 12c: SQL

3rd Edition

ISBN:9781305251038

Author:Joan Casteel

Publisher:Joan Casteel

Chapter12: Subqueries And Merge Statements

Section: Chapter Questions

Problem 6MC

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The database contains a Horse table, with columns: ID integer, primary key Registered Name variable-length string. The database contains a Student table, with columns: • ID integer, primary key First Name - variable-length string LastName variable-length string Write a SQL Query to create a Schedule table, with columns: HorseID - integer with range 0 to 65535, not NULL • Student ID integer with range 0 to 65535 Lesson DateTime - date/time, not NULL (HorseID, Lesson DateTime) is the primary key Also, create the following foreign key constraints on Schedule columns: HorseID references Horse. When an ID is deleted from Horse matching Lesson Schedule rows are deleted. Student ID references Student. When an ID is deleted from Student, matching Student ID 's are set to NULL).
Please write a query for dvdrental database. Please list all the customers. For each customer display following information: • Customer Id • First Name • Last Name • Rental price for most expensive movie rented in May 2005 by this customer • Rental price for most expensive movie rented in June 2005 by this customer • Rental price for most expensive movie rented in July 2005 by this customer Final query should have 6 columns, one row for each customer For rental price use “rental_rate” column from film table. Sort results by customer last name. postgres
Database https://www.w3schools.com/sql/trysql.asp?filename=trysql_select_all
SQL: Create a SQL query that uses a correlated subquery to display the descriptions for products provided by a vendor in area code 904. The outer query will use the PRODUCT table, then use WHERE EXISTS, then the subquery which will use the VENDOR and PRODUCT tables via a join (a join should be used here). [hint: you should have 3 records of output]. My code: select p_descript from product where exist(select v_areacode from vendor where v_areacode = '904') ; I am getting an error but I can't see what is missing. ORA-00936: missing expression
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