Use the molecular orbital model to fully describe the bonding in O2+, 02, 02, and 022". Determine which of the following statements are true and which are false. E The electron configuration of 0,* is (o 25)?(02s*)?(02p)?(n2p)*(n2p*)2. The bond lengths increase in the order: 02²- < 02° < O2 < 02+. O The bond order in 02+ and O2 is, respectively, 1.5 and 2. The electron configuration of 02 is (025)²(02s*)²(02p)?(n2p)^(n2p*)4. OBond length increases with increasing bond order while bond energy decreases. CThe number of unpaired electrons in O2* and O22 is, respectively, 1 and 2.

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Use the molecular orbital model to fully describe the bonding in 02+, 02, 02, and 022.
Determine which of the following statements are true and which are false.
The electron configuration of 02+ is (0 25)²(025*)?(02p)²(n2p)*(n2p*)?.
O The bond lengths increase in the order: 022- < 02° < 02 < 02+.
2s.
The bond order in 02+ and O2 is, respectively, 1.5 and 2.
The electron configuration of O2 is (025)²(02s*)²(02p)?(n2p)^(n2p*)*.
O Bond length increases with increasing bond order while bond energy decreases.
The number of unpaired electrons in O2+ and O22 is, respectively, 1 and 2.
Transcribed Image Text:Use the molecular orbital model to fully describe the bonding in 02+, 02, 02, and 022. Determine which of the following statements are true and which are false. The electron configuration of 02+ is (0 25)²(025*)?(02p)²(n2p)*(n2p*)?. O The bond lengths increase in the order: 022- < 02° < 02 < 02+. 2s. The bond order in 02+ and O2 is, respectively, 1.5 and 2. The electron configuration of O2 is (025)²(02s*)²(02p)?(n2p)^(n2p*)*. O Bond length increases with increasing bond order while bond energy decreases. The number of unpaired electrons in O2+ and O22 is, respectively, 1 and 2.
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