Use the method of undetermined coefficients to solve the given nonhomogeneous system. 1 4 -7 *-( * )* - ()- X' = 3 + 10 9 6 X(t) =

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### Solving a Nonhomogeneous System Using the Method of Undetermined Coefficients

To solve the given nonhomogeneous system of differential equations using the method of undetermined coefficients, follow the steps below:

The system is given as:
\[ \mathbf{X}' = \begin{pmatrix} 4 & \frac{1}{3} \\ 9 & 6 \end{pmatrix} \mathbf{X} + \begin{pmatrix} -7 \\ 10 \end{pmatrix} e^t \]

where \( \mathbf{X}(t) = \begin{pmatrix} x_1(t) \\ x_2(t) \end{pmatrix} \).

1. **Find the General Solution of the Homogeneous System:**
   ```math
   \mathbf{X}' = \begin{pmatrix} 4 & \frac{1}{3} \\ 9 & 6 \end{pmatrix} \mathbf{X}
   ```

2. **Determine the Particular Solution:**  
   Assume a particular solution of the form:
   ```math
   \mathbf{X}_p(t) = \begin{pmatrix} x_{1p}(t) \\ x_{2p}(t) \end{pmatrix} = \begin{pmatrix} A \\ B \end{pmatrix} e^t
   ```

3. **Substitute the Particular Solution Back into the Nonhomogeneous Equation:**
   ```math
   \begin{pmatrix} x_{1p}' \\ x_{2p}' \end{pmatrix} = \begin{pmatrix} 4 & \frac{1}{3} \\ 9 & 6 \end{pmatrix} \begin{pmatrix} x_{1p} \\ x_{2p} \end{pmatrix} + \begin{pmatrix} -7 \\ 10 \end{pmatrix} e^t
   ```

   Substitute \(\mathbf{X}_p(t) = \begin{pmatrix} A \\ B \end{pmatrix} e^t \) and solve for \( A \) and \( B \).

4. **Combine the General Solution and Particular Solution:**
   ```math
   \mathbf{X}(t) = \mathbf{X}_h(t) + \mathbf{X}_p(t)
   ```
Transcribed Image Text:### Solving a Nonhomogeneous System Using the Method of Undetermined Coefficients To solve the given nonhomogeneous system of differential equations using the method of undetermined coefficients, follow the steps below: The system is given as: \[ \mathbf{X}' = \begin{pmatrix} 4 & \frac{1}{3} \\ 9 & 6 \end{pmatrix} \mathbf{X} + \begin{pmatrix} -7 \\ 10 \end{pmatrix} e^t \] where \( \mathbf{X}(t) = \begin{pmatrix} x_1(t) \\ x_2(t) \end{pmatrix} \). 1. **Find the General Solution of the Homogeneous System:** ```math \mathbf{X}' = \begin{pmatrix} 4 & \frac{1}{3} \\ 9 & 6 \end{pmatrix} \mathbf{X} ``` 2. **Determine the Particular Solution:** Assume a particular solution of the form: ```math \mathbf{X}_p(t) = \begin{pmatrix} x_{1p}(t) \\ x_{2p}(t) \end{pmatrix} = \begin{pmatrix} A \\ B \end{pmatrix} e^t ``` 3. **Substitute the Particular Solution Back into the Nonhomogeneous Equation:** ```math \begin{pmatrix} x_{1p}' \\ x_{2p}' \end{pmatrix} = \begin{pmatrix} 4 & \frac{1}{3} \\ 9 & 6 \end{pmatrix} \begin{pmatrix} x_{1p} \\ x_{2p} \end{pmatrix} + \begin{pmatrix} -7 \\ 10 \end{pmatrix} e^t ``` Substitute \(\mathbf{X}_p(t) = \begin{pmatrix} A \\ B \end{pmatrix} e^t \) and solve for \( A \) and \( B \). 4. **Combine the General Solution and Particular Solution:** ```math \mathbf{X}(t) = \mathbf{X}_h(t) + \mathbf{X}_p(t) ```
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