Use the method of cylindrical shells to find the volume generated by rotating the region bounded by the graphs of the given equations about the y-axis. y = 5√√x, y = 0, x = 1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**Finding the Volume Using the Method of Cylindrical Shells**

To determine the volume generated by rotating the region bounded by the curves about the y-axis, apply the method of cylindrical shells. The equations provided for the curves are:

\[ y = 5\sqrt[3]{x}, \quad y = 0, \quad x = 1 \]

### Step-by-Step Solution:

1. **Identify the Boundaries:**
   - The first equation \( y = 5\sqrt[3]{x} \) represents a curve.
   - The second equation \( y = 0 \) represents the x-axis.
   - The third boundary \( x = 1 \) is a vertical line.

2. **Setup for the Method of Cylindrical Shells:**
   - When rotating around the y-axis, the height of each cylindrical shell is given by the function \( y = 5\sqrt[3]{x} \).
   - The radius of each cylindrical shell is \( x \).

3. **Volume of a Single Shell:**
   - The volume of a shell is given by \( 2\pi \times (\text{radius}) \times (\text{height}) \times (\text{thickness}) \).
   - The thickness here is \( dx \).
   - Thus, the volume element is \( dV = 2\pi x \cdot 5\sqrt[3]{x} \cdot dx \).

4. **Integrate to Find the Total Volume:**
   - Integrate with respect to \( x \) from 0 to 1.

   \[
   V = \int_{0}^{1} 2\pi x \cdot 5\sqrt[3]{x} \, dx
   \]

5. **Simplify the Integral:**

   \[
   V = 10\pi \int_{0}^{1} x \cdot x^{1/3} \, dx = 10\pi \int_{0}^{1} x^{4/3} \, dx
   \]

6. **Evaluate the Integral:**
   - The integral \( \int x^{4/3} \, dx \) can be evaluated using the power rule:

   \[
   \int x^{4/3} \, dx = \frac{3}{7} x^{7/3} 
   \]
Transcribed Image Text:**Finding the Volume Using the Method of Cylindrical Shells** To determine the volume generated by rotating the region bounded by the curves about the y-axis, apply the method of cylindrical shells. The equations provided for the curves are: \[ y = 5\sqrt[3]{x}, \quad y = 0, \quad x = 1 \] ### Step-by-Step Solution: 1. **Identify the Boundaries:** - The first equation \( y = 5\sqrt[3]{x} \) represents a curve. - The second equation \( y = 0 \) represents the x-axis. - The third boundary \( x = 1 \) is a vertical line. 2. **Setup for the Method of Cylindrical Shells:** - When rotating around the y-axis, the height of each cylindrical shell is given by the function \( y = 5\sqrt[3]{x} \). - The radius of each cylindrical shell is \( x \). 3. **Volume of a Single Shell:** - The volume of a shell is given by \( 2\pi \times (\text{radius}) \times (\text{height}) \times (\text{thickness}) \). - The thickness here is \( dx \). - Thus, the volume element is \( dV = 2\pi x \cdot 5\sqrt[3]{x} \cdot dx \). 4. **Integrate to Find the Total Volume:** - Integrate with respect to \( x \) from 0 to 1. \[ V = \int_{0}^{1} 2\pi x \cdot 5\sqrt[3]{x} \, dx \] 5. **Simplify the Integral:** \[ V = 10\pi \int_{0}^{1} x \cdot x^{1/3} \, dx = 10\pi \int_{0}^{1} x^{4/3} \, dx \] 6. **Evaluate the Integral:** - The integral \( \int x^{4/3} \, dx \) can be evaluated using the power rule: \[ \int x^{4/3} \, dx = \frac{3}{7} x^{7/3} \]
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