Use the limit laws to derive the product rule of derivatives (fg)' = f'g+ fg' by filling in the blanks: Let f and g be differentiable functions. Then: (fg)'(x) = lim definition of derivative h→0 = lim substitute (fg)(x) = f(x)g(x) h→0 - f(x)g(x+h) + = lim h→0 add & subt. f(x)g(x + h) - f(x)g(x + h) f(x)g(x+h) = lim h→0 break up fraction g(x + h) f(=) ( = lim factor h→0 = lim 9(x + h) + lim ( f(x)- using sum rule of limits h→0 h>0 lim g(x + h) \h→0 lim f(x) h→0 lim lim using product rule of limits h>0 h→0 lim + lim evaluate limits by direct sub. h→0 h>0 = f'(x)g(x) + f(x)g'(x) definition of derivatives ||

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Use the limit laws to derive the product rule of derivatives (fg)' = f'g+ fg' by filling in the blanks:
Let f and g be differentiable functions. Then:
(fg)'(x)
= lim
definition of derivative
h→0
= lim
substitute (fg)(x) = f(x)g(x)
h→0
- f(x)g(x+h) +
= lim
h→0
add & subt. f(x)g(x + h)
- f(x)g(x + h)
f(x)g(x+h)
= lim
h→0
break up fraction
g(x + h)
f(=) (
= lim
factor
h→0
= lim
9(x + h)
+ lim ( f(x)-
using sum rule of limits
h→0
h>0
lim g(x + h)
\h→0
lim f(x)
h→0
lim
lim
using product rule of limits
h>0
h→0
lim
lim
evaluate limits by direct sub.
h→0
h>0
= f'(x)g(x) + f(x)g'(x)
definition of derivatives
||
Transcribed Image Text:Use the limit laws to derive the product rule of derivatives (fg)' = f'g+ fg' by filling in the blanks: Let f and g be differentiable functions. Then: (fg)'(x) = lim definition of derivative h→0 = lim substitute (fg)(x) = f(x)g(x) h→0 - f(x)g(x+h) + = lim h→0 add & subt. f(x)g(x + h) - f(x)g(x + h) f(x)g(x+h) = lim h→0 break up fraction g(x + h) f(=) ( = lim factor h→0 = lim 9(x + h) + lim ( f(x)- using sum rule of limits h→0 h>0 lim g(x + h) \h→0 lim f(x) h→0 lim lim using product rule of limits h>0 h→0 lim lim evaluate limits by direct sub. h→0 h>0 = f'(x)g(x) + f(x)g'(x) definition of derivatives ||
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