Use the limit comparison test to prove that the series converges or diverges. (a) 2n +4n-n² 5n+n³ +4√√n (b) 4n5/2 +5n³/2-3n+1 n¹1/3 + 2n³/2 — n¹/³ – 1 n7/³-n²ln(n) - n7/4 (c) Σ n³/2 +2n4/³(ln(n))² — n n=100

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