Use the Law of Cosines to determine the indicated side x. (Assume b = 10 and c = 2. Round your answer to one decimal place.) X = C b. 88° A

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**Title:** Solving for Side Length Using the Law of Cosines

**Objective:** Use the Law of Cosines to determine the indicated side \( x \). Assume \( b = 10 \) and \( c = 2 \). Round your answer to one decimal place.

**Diagram Description:**

- The triangle \( \triangle ABC \) is depicted with:
  - Angle \( A = 88^\circ \)
  - Side \( b \) opposite angle \( B \) labeled as \( b = 10 \)
  - Side \( c \) opposite angle \( C \) labeled as \( c = 2 \)
  - Side \( x \) opposite angle \( A \) which is the side to be determined.

**Steps to Solve:**

To find the length of side \( x \), apply the Law of Cosines:

\[
x^2 = b^2 + c^2 - 2bc \cdot \cos(A)
\]

Substitute the given values:

\[
x^2 = 10^2 + 2^2 - 2 \times 10 \times 2 \times \cos(88^\circ)
\]

Next, compute the cosine of \( 88^\circ \) and substitute the value to solve for \( x \).

After calculating, remember to round the answer to one decimal place. 

**Conclusion:**

This exercise illustrates the application of the Law of Cosines in solving triangles where the sides and angles interact based on known values of other sides and angles.
Transcribed Image Text:**Title:** Solving for Side Length Using the Law of Cosines **Objective:** Use the Law of Cosines to determine the indicated side \( x \). Assume \( b = 10 \) and \( c = 2 \). Round your answer to one decimal place. **Diagram Description:** - The triangle \( \triangle ABC \) is depicted with: - Angle \( A = 88^\circ \) - Side \( b \) opposite angle \( B \) labeled as \( b = 10 \) - Side \( c \) opposite angle \( C \) labeled as \( c = 2 \) - Side \( x \) opposite angle \( A \) which is the side to be determined. **Steps to Solve:** To find the length of side \( x \), apply the Law of Cosines: \[ x^2 = b^2 + c^2 - 2bc \cdot \cos(A) \] Substitute the given values: \[ x^2 = 10^2 + 2^2 - 2 \times 10 \times 2 \times \cos(88^\circ) \] Next, compute the cosine of \( 88^\circ \) and substitute the value to solve for \( x \). After calculating, remember to round the answer to one decimal place. **Conclusion:** This exercise illustrates the application of the Law of Cosines in solving triangles where the sides and angles interact based on known values of other sides and angles.
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