Use the Laplace transform to solve the given initial-value problem. y" + 6y' + 34y = 5(t – x) + 6(t - 5x), y(0) = 1, y'(0) = 0 ) •([ ]) «(e - «) + ([ ) «(e - y(t) = +

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Problem Statement**: Use the Laplace transform to solve the given initial-value problem. 

**Equation**:  
\[ y'' + 6y' + 34y = \delta(t - \pi) + \delta(t - 5\pi) \]

**Initial Conditions**:  
\[ y(0) = 1, \quad y'(0) = 0 \]

**Solution Form**:  
\[ y(t) = \left( \,\, \boxed{\phantom{solution}} \,\, \right) + \left( \,\, \boxed{\phantom{solution}} \,\, \right) \cdot u(t - \pi) + \left( \,\, \boxed{\phantom{solution}} \,\, \right) \cdot u(t - \boxed{\phantom{solution}}) \]

*Note*: The equation contains the Dirac delta function \(\delta\) at \(t = \pi\) and \(t = 5\pi\), and incorporates Heaviside step functions \(u(t - \pi)\) and \(u(t - 5\pi)\) in the solution. The boxes represent placeholders for components of the solution derived using Laplace transforms.
Transcribed Image Text:**Problem Statement**: Use the Laplace transform to solve the given initial-value problem. **Equation**: \[ y'' + 6y' + 34y = \delta(t - \pi) + \delta(t - 5\pi) \] **Initial Conditions**: \[ y(0) = 1, \quad y'(0) = 0 \] **Solution Form**: \[ y(t) = \left( \,\, \boxed{\phantom{solution}} \,\, \right) + \left( \,\, \boxed{\phantom{solution}} \,\, \right) \cdot u(t - \pi) + \left( \,\, \boxed{\phantom{solution}} \,\, \right) \cdot u(t - \boxed{\phantom{solution}}) \] *Note*: The equation contains the Dirac delta function \(\delta\) at \(t = \pi\) and \(t = 5\pi\), and incorporates Heaviside step functions \(u(t - \pi)\) and \(u(t - 5\pi)\) in the solution. The boxes represent placeholders for components of the solution derived using Laplace transforms.
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