Use the Laplace Transform to solve the given initial value problem. y" - 2y' + 2y = cos t; y(0) = 1, y'(0) = 1 y = 5(cost - 2 sint = 4e^tcost + 3e^tsint) O y = 5(cost - 2 sint = 4e^tcost - 3e^tsint) O y = (1/5)(cost - 2 sint = 4e^tcost + 3e^tsint) Oy=(1/5)(cost - 2 sint = 4e^tcost - 3e^tsint)

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Use the Laplace Transform to solve the given initial value problem.
y" - 2y' + 2y = cos t; y(0) = 1, y'(0) = 1
y = 5(cost - 2 sint = 4e^tcost + 3e^tsint)
O y = 5(cost - 2 sint = 4e^tcost - 3e^tsint)
O y = (1/5)(cost - 2 sint = 4e^tcost + 3e^tsint)
O y = (1/5)(cost - 2 sint = 4e^tcost - 3e^tsint)
Transcribed Image Text:Use the Laplace Transform to solve the given initial value problem. y" - 2y' + 2y = cos t; y(0) = 1, y'(0) = 1 y = 5(cost - 2 sint = 4e^tcost + 3e^tsint) O y = 5(cost - 2 sint = 4e^tcost - 3e^tsint) O y = (1/5)(cost - 2 sint = 4e^tcost + 3e^tsint) O y = (1/5)(cost - 2 sint = 4e^tcost - 3e^tsint)
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