32. Solve: Vx 8 V2x9 =1 -

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
32. Solve: Vx 8 V2x9 =1
-
Transcribed Image Text:32. Solve: Vx 8 V2x9 =1 -
Expert Solution
Step 1

We add sqrt(2x+9) to both sides

VX+8-2x+9 =1
Or, V+8 1+ /2x+9
Step 2

Then we square both sides.Then we simplify right side. Later subtracted 2x and 10 from both sides.

Vx+8 12x+9
Or, +8)(1+2x+9
Or, X+8 1+22x+9 +2x+9
Or, X+8 2x+10+2/2x+9
Or, -x-2-2V2X+9
2
Step 3

We square both sides again

 

-х-232 2х+9
Or, x-2)(22x+9 )
Or, x2+4x+4 4(2x+9)
Or, x2+4x+4-8x+36
Or, х?-4x-32-0
Оr, (x+4)(х-8)-0
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