Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![32. Solve: Vx 8 V2x9 =1
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffb2f6727-678b-4d19-be4d-85e980f61741%2F017acea1-87ba-4c2b-85bc-d735393384d0%2Fq9p22n6.png&w=3840&q=75)
Transcribed Image Text:32. Solve: Vx 8 V2x9 =1
-
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
We add sqrt(2x+9) to both sides
![VX+8-2x+9 =1
Or, V+8 1+ /2x+9](https://content.bartleby.com/qna-images/answer/fb2f6727-678b-4d19-be4d-85e980f61741/e862d34d-d868-498d-819e-26cb9360f35c/dk1vnwf.png)
Step 2
Then we square both sides.Then we simplify right side. Later subtracted 2x and 10 from both sides.
![Vx+8 12x+9
Or, +8)(1+2x+9
Or, X+8 1+22x+9 +2x+9
Or, X+8 2x+10+2/2x+9
Or, -x-2-2V2X+9
2](https://content.bartleby.com/qna-images/answer/fb2f6727-678b-4d19-be4d-85e980f61741/e862d34d-d868-498d-819e-26cb9360f35c/kvbcstq.png)
Step 3
We square both sides again
![-х-232 2х+9
Or, x-2)(22x+9 )
Or, x2+4x+4 4(2x+9)
Or, x2+4x+4-8x+36
Or, х?-4x-32-0
Оr, (x+4)(х-8)-0](https://content.bartleby.com/qna-images/answer/fb2f6727-678b-4d19-be4d-85e980f61741/e862d34d-d868-498d-819e-26cb9360f35c/jmbcakr.png)
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