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Use the Jacobi method to find approximate solutions to - 4x3 201 + 2x2 + 3x3 = 25 2.x1 - 12 + 5x3 = 6 3x1 + 10x2 starting the initial values 1 = 1, x2 = 1 ,and r3 1.2 and iterating until error is less than 2%. Round-off answer to 5 decimal places. Reminder: Arrange the system to be Diagonally Dominant before iteration. O x1 =1.00022, x2 -0.99960, x3 =0.99956 O x1 =0.99893, x2 1.00254, x3 1.00155 O x1 =1.00092, x2 0.99867, x3 -0.99761 O x1 =0.99789, x2 1.00353, x3 1.00476 none of the choices

Use the Jacobi method to find approximate solutions to - 4x3 201 + 2x2 + 3x3 = 25 2.x1 - 12 + 5x3 = 6 3x1 + 10x2 starting the initial values 1 = 1, x2 = 1 ,and r3 1.2 and iterating until error is less than 2%. Round-off answer to 5 decimal places. Reminder: Arrange the system to be Diagonally Dominant before iteration. O x1 =1.00022, x2 -0.99960, x3 =0.99956 O x1 =0.99893, x2 1.00254, x3 1.00155 O x1 =1.00092, x2 0.99867, x3 -0.99761 O x1 =0.99789, x2 1.00353, x3 1.00476 none of the choices

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use the Jacobi method to find approximate solutions to 3x1 + 10x2 - 4x3 201 + 2x2 + 3x3 = 25 2x1 2 +5x3 = 6 I2 + 523 starting the initial values 1 =1,x2 1,and r3 1.2 and iterating until error is less than 2%. Round-off answer to 5 decimal places. Reminder: Arrange the system to be Diagonally Dominant before iteration. O x1 =1.00022, x2 =0.99960, x3 =0.99956 %3D O x1 =0.99893, x2 -1.00254.xg =1.00155 O x1 =1.00092, x2 -0.99867, x3 =0.99761 O x1 =0.99789, x2 =1.00353, x3 -1.00476 O none of the choices
Transcribed Image Text:Use the Jacobi method to find approximate solutions to 3x1 + 10x2 - 4x3 201 + 2x2 + 3x3 = 25 2x1 2 +5x3 = 6 I2 + 523 starting the initial values 1 =1,x2 1,and r3 1.2 and iterating until error is less than 2%. Round-off answer to 5 decimal places. Reminder: Arrange the system to be Diagonally Dominant before iteration. O x1 =1.00022, x2 =0.99960, x3 =0.99956 %3D O x1 =0.99893, x2 -1.00254.xg =1.00155 O x1 =1.00092, x2 -0.99867, x3 =0.99761 O x1 =0.99789, x2 =1.00353, x3 -1.00476 O none of the choices
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