Use the intermediate value theorem to determine whether the function f(x) = x³ + x-4 has a root or not between x = 1 and x = 2. If yes, then find the root to five decimal places. Does the given function have a root between the interval [1, 2]? If yes, then find the root. Choose the correct answer below. O A. Yes, the given function has a root between [1, 2] and the root is (Type an integer or decimal rounded to five decimal places as needed.) C O B. No, the given function has no root between [1, 2].
Use the intermediate value theorem to determine whether the function f(x) = x³ + x-4 has a root or not between x = 1 and x = 2. If yes, then find the root to five decimal places. Does the given function have a root between the interval [1, 2]? If yes, then find the root. Choose the correct answer below. O A. Yes, the given function has a root between [1, 2] and the root is (Type an integer or decimal rounded to five decimal places as needed.) C O B. No, the given function has no root between [1, 2].
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![**Using the Intermediate Value Theorem**
To determine whether the function \( f(x) = x^3 + x - 4 \) has a root between \( x = 1 \) and \( x = 2 \), apply the Intermediate Value Theorem. If the function changes sign over the interval, it indicates the presence of a root.
**Question:**
Does the given function have a root between the interval \([1, 2]\)? If yes, then find the root. Choose the correct answer below.
- **A.** Yes, the given function has a root between \([1, 2]\) and the root is \(\_\_\_\_\_\).
*(Type an integer or decimal rounded to five decimal places as needed.)*
- **B.** No, the given function has no root between \([1, 2]\).
**Explanation:**
Check the values of \( f(x) \) at \( x = 1 \) and \( x = 2 \):
1. Calculate \( f(1) = 1^3 + 1 - 4 = -2 \).
2. Calculate \( f(2) = 2^3 + 2 - 4 = 6 \).
Since \( f(1) = -2 \) and \( f(2) = 6 \), and the function changes sign from negative to positive, there is a root in the interval \([1, 2]\). Further numerical methods or graphing would be required to find the root to five decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F256dbc8b-2bc9-463c-8f55-d3702041f8b6%2F73e08e24-a3e1-4bcf-bd1c-c82e9a802303%2Fxgznsu_processed.png&w=3840&q=75)
Transcribed Image Text:**Using the Intermediate Value Theorem**
To determine whether the function \( f(x) = x^3 + x - 4 \) has a root between \( x = 1 \) and \( x = 2 \), apply the Intermediate Value Theorem. If the function changes sign over the interval, it indicates the presence of a root.
**Question:**
Does the given function have a root between the interval \([1, 2]\)? If yes, then find the root. Choose the correct answer below.
- **A.** Yes, the given function has a root between \([1, 2]\) and the root is \(\_\_\_\_\_\).
*(Type an integer or decimal rounded to five decimal places as needed.)*
- **B.** No, the given function has no root between \([1, 2]\).
**Explanation:**
Check the values of \( f(x) \) at \( x = 1 \) and \( x = 2 \):
1. Calculate \( f(1) = 1^3 + 1 - 4 = -2 \).
2. Calculate \( f(2) = 2^3 + 2 - 4 = 6 \).
Since \( f(1) = -2 \) and \( f(2) = 6 \), and the function changes sign from negative to positive, there is a root in the interval \([1, 2]\). Further numerical methods or graphing would be required to find the root to five decimal places.
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