Explain why y = x - 5 has at least two roots. 'A. Intermediate-value theorem B. Sandwich theorem C. Bisection method This theorem or method needs to be applied on an interval. To apply this theorem, the function values at the endpoints must have opposite signs. Show that f(x) = x² - 5 satisfies this condition for two intervals. Select the correct choice below and fill in the answer boxes to complete your choice. O A. Since f(0) = and f( - 3) = f(3) =, f(0) < 0 < f( - 3) and f(3) < 0

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Explain why y = x - 5 has at least two roots.
A. Intermediate-value theorem
B. Sandwich theorem
C. Bisection method
This theorem or method needs to be applied on an interval. To apply this theorem, the function values at the endpoints must have opposite signs. Show that
f(x) =x - 5 satisfies this condition for two intervals. Select the correct choice below and fill in the answer boxes to complete your choice.
O A. Since f(0) =
and f( - 3) = f(3) =
f(0) < 0 <f(- 3) and f(3) < 0 < f(0).
O B. Since f(0) =
and f( - 3) = f(3) =
f( – 3) < 0 < f(0) and f(0) < 0 < f(3).
OC. Since f(0) =
and f( - 3) = f(3) =
f( – 3) < 0 < f(0) and f(3) < 0 < f(0).
O D. Since f(0) =
and f(- 3) = f(3) = f(0) < 0 < f(- 3) and f(0) < 0 < f(3).
Transcribed Image Text:Explain why y = x - 5 has at least two roots. A. Intermediate-value theorem B. Sandwich theorem C. Bisection method This theorem or method needs to be applied on an interval. To apply this theorem, the function values at the endpoints must have opposite signs. Show that f(x) =x - 5 satisfies this condition for two intervals. Select the correct choice below and fill in the answer boxes to complete your choice. O A. Since f(0) = and f( - 3) = f(3) = f(0) < 0 <f(- 3) and f(3) < 0 < f(0). O B. Since f(0) = and f( - 3) = f(3) = f( – 3) < 0 < f(0) and f(0) < 0 < f(3). OC. Since f(0) = and f( - 3) = f(3) = f( – 3) < 0 < f(0) and f(3) < 0 < f(0). O D. Since f(0) = and f(- 3) = f(3) = f(0) < 0 < f(- 3) and f(0) < 0 < f(3).
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