Use the information in the provided sketch below to obtain the following information: A ball travels horizontally off of a table 0.78 m high and lands 0.96 m away. (a) Determine the time it takes the ball to reach the ground. (b) Determine the initial horizontal speed of the ball just as it leaves the table. (c) Determine the initial vertical speed of the ball just as it leaves the table. Ay = 0.78 m
Use the information in the provided sketch below to obtain the following information: A ball travels horizontally off of a table 0.78 m high and lands 0.96 m away. (a) Determine the time it takes the ball to reach the ground. (b) Determine the initial horizontal speed of the ball just as it leaves the table. (c) Determine the initial vertical speed of the ball just as it leaves the table. Ay = 0.78 m
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Projectile Motion Analysis**
In the provided sketch, a ball is shown traveling horizontally off a table, which is 0.78 meters high, and lands 0.96 meters away from the base of the table.
- **Vertical Displacement (\(\Delta y\)):** The vertical distance from the top of the table to the ground is 0.78 meters.
- **Horizontal Displacement (\(\Delta x\)):** The horizontal distance from the table to the point where the ball lands is 0.96 meters.
**Tasks:**
(a) **Determine the time it takes for the ball to reach the ground.**
(b) **Calculate the initial horizontal speed of the ball as it leaves the table.**
(c) **Determine the initial vertical speed of the ball just as it leaves the table.**
**Diagram Explanation:**
The diagram illustrates a right-angled path, where the vertical leg represents the height of the table (0.78 m) and the horizontal leg represents the distance traveled by the ball horizontally (0.96 m) before landing. The blue circle indicates the ball's position at different stages.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F829812ca-fcc6-4eb6-9db8-017261f61931%2F6e0ac685-f6cc-42b3-9da9-a2126349a810%2F6yotsph_processed.png&w=3840&q=75)
Transcribed Image Text:**Projectile Motion Analysis**
In the provided sketch, a ball is shown traveling horizontally off a table, which is 0.78 meters high, and lands 0.96 meters away from the base of the table.
- **Vertical Displacement (\(\Delta y\)):** The vertical distance from the top of the table to the ground is 0.78 meters.
- **Horizontal Displacement (\(\Delta x\)):** The horizontal distance from the table to the point where the ball lands is 0.96 meters.
**Tasks:**
(a) **Determine the time it takes for the ball to reach the ground.**
(b) **Calculate the initial horizontal speed of the ball as it leaves the table.**
(c) **Determine the initial vertical speed of the ball just as it leaves the table.**
**Diagram Explanation:**
The diagram illustrates a right-angled path, where the vertical leg represents the height of the table (0.78 m) and the horizontal leg represents the distance traveled by the ball horizontally (0.96 m) before landing. The blue circle indicates the ball's position at different stages.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given,
A ball horizontally off the table 0.78 m high and lands 0.96 m away.
So initial vertical speed is 0 m/s .
Let the time be t and horizontal speed be vx.
We know that vertical acceleration is acceleration due to gravity = 9.8 m/s2 and horizontal acceleration is 0 m/s2.
So using kinematic relation ,
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