Use the given ΔH°f values in the table to calculate the ΔH°rxn of the reaction below. 2NH3(l) + 6NO(g) → 3H2O2(l) + 4N2(g)

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Use the given ΔH°f values in the table to calculate the ΔH°rxn of the reaction below.

2NH3(l) + 6NO(g) → 3H2O2(l) + 4N2(g)

### Calculating Reaction Enthalpy Change

**Objective**: Use the given standard enthalpy of formation (\(\Delta H^\circ_f\)) values to calculate the standard enthalpy change (\(\Delta H^\circ_{rxn}\)) of the reaction below.

**Chemical Reaction**:
\[ 2\text{NH}_3(l) + 6\text{NO}(g) \rightarrow 3\text{H}_2\text{O}_2(l) + 4\text{N}_2(g) \]

**Table of Enthalpy Values**:

| Substance | \(\Delta H^\circ_f\) (kJ/mol) |
|-----------|-------------------------------|
| NH\(_3\)(l) | 264.0                         |
| NO(g)      | 90.3                          |
| H\(_2\)O\(_2\)(l) | -187.8                   |

**Question**:  
Calculate \(\Delta H^\circ_{rxn}\) using the options below:

- \(-1633.2 \, \text{kJ}\)
- \(-577.2 \, \text{kJ}\)
- \(-542.1 \, \text{kJ}\)
- \(-506.4 \, \text{kJ}\)

**Method**:

To determine \(\Delta H^\circ_{rxn}\), use the formula:
\[
\Delta H^\circ_{rxn} = \sum \Delta H^\circ_f (\text{products}) - \sum \Delta H^\circ_f (\text{reactants})
\]
Transcribed Image Text:### Calculating Reaction Enthalpy Change **Objective**: Use the given standard enthalpy of formation (\(\Delta H^\circ_f\)) values to calculate the standard enthalpy change (\(\Delta H^\circ_{rxn}\)) of the reaction below. **Chemical Reaction**: \[ 2\text{NH}_3(l) + 6\text{NO}(g) \rightarrow 3\text{H}_2\text{O}_2(l) + 4\text{N}_2(g) \] **Table of Enthalpy Values**: | Substance | \(\Delta H^\circ_f\) (kJ/mol) | |-----------|-------------------------------| | NH\(_3\)(l) | 264.0 | | NO(g) | 90.3 | | H\(_2\)O\(_2\)(l) | -187.8 | **Question**: Calculate \(\Delta H^\circ_{rxn}\) using the options below: - \(-1633.2 \, \text{kJ}\) - \(-577.2 \, \text{kJ}\) - \(-542.1 \, \text{kJ}\) - \(-506.4 \, \text{kJ}\) **Method**: To determine \(\Delta H^\circ_{rxn}\), use the formula: \[ \Delta H^\circ_{rxn} = \sum \Delta H^\circ_f (\text{products}) - \sum \Delta H^\circ_f (\text{reactants}) \]
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