Use the given values Air as an ideal gas flows through the turbine and heat exchanger arrangement. Steady-state data are given on the figure and on the table. Stray heat transfer and kinetic and potential energy effects can be ignored.a) Determine the power developed, ? ̇ in Turbine 2Find the rates of entropy production, ?̇ each in kW/K, forb) Turbine 1 andc) Heat exchangerd) Which component contributes more to inefficient operation of the overall system? How do you know? Wa = 10,000 kWW2 = ?TurbineTurbine1P3 = 4.5 barT3 = ?T2 = 1100 KP2 =5 barT4 = 980 KP4 =1 barwwwwwwwAirin124.T1= 1500T;= 1480 K-9-KHeat exchangerPs = 1.35 barVT6 = 1200 KP6 =1 barsinAirinState12345unitsTurbine 1Turbine 2Heat ExchangerTK15001100136998014801200bar205.04.51.01.351.0kJ/kg1635.971161.11478.281023.31611.81277.8s°kJ/(kg K)3.445163.077323.335042.944683.428923.17888kg/sec21.121.121.121.12020

Answered: Use the given values Air as an ideal…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Use the given values Air as an ideal gas flows through the turbine and heat exchanger arrangement. Steady-state data are given on the figure and on the table. Stray heat transfer and kinetic and potential energy effects can be ignored.

a) Determine the power developed, ? ̇ in Turbine 2

Find the rates of entropy production, ?̇ each in kW/K, for

b) Turbine 1 and
c) Heat exchanger
d) Which component contributes more to inefficient operation of the overall system? How do you know?

Wa = 10,000 kW
W2 = ?
Turbine
Turbine
1
P3 = 4.5 bar
T3 = ?
T2 = 1100 K
P2 =5 bar
T4 = 980 K
P4 =1 bar
www
wwww
Air
in
1
2
4.
T1= 1500
T;= 1480 K
-9-
K
Heat exchanger
Ps = 1.35 bar
VT6 = 1200 K
P6 =1 bar
sin
Air
in
State
1
2
3
4
5
units
Turbine 1
Turbine 2
Heat Exchanger
T
K
1500
1100
1369
980
1480
1200
bar
20
5.0
4.5
1.0
1.35
1.0
kJ/kg
1635.97
1161.1
1478.28
1023.3
1611.8
1277.8
s°
kJ/(kg K)
3.44516
3.07732
3.33504
2.94468
3.42892
3.17888
kg/sec
21.1
21.1
21.1
21.1
20
20

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