Use the given graph of f to find a number & such that if |x-1| < 8 then [f(x) - 1| < 0.2. 8 = 1.2 1 0.8 0.7 1 1.1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Q1. Please answer the question

**Title: Understanding Limits with Graphical Analysis**

**Objective:**
Use the given graph of the function \( f \) to determine a number \( \delta \) such that if \( |x - 1| < \delta \), then \( |f(x) - 1| < 0.2 \).

**Graph Explanation:**
The graph displays a curve representing the function \( f \). The x-axis is labeled \( x \) and the y-axis is labeled \( y \).

Key points on the graph:
- The curve \( f \) passes through key y-values at 1.2 and 0.8.
- Horizontal lines span these y-values to indicate the possible values for \( f(x) \) that are within 0.2 units of 1.
- Vertical lines highlight the corresponding x-values on the graph centered around \( x = 1 \).
- Specifically, the vertical lines demarcate the interval \( x = 0.7 \) and \( x = 1.1 \).

**Task:**
Identify \( \delta \) by observing where the lines parallel to \( y = 1 \) intersect the curve \( f \). You should determine \( \delta \) such that \( |x - 1| < \delta \) implies \( 0.8 < f(x) < 1.2 \).

**Solution:**
From the graph, we can observe that for the interval \( 0.7 < x < 1.1 \), the function \( f(x) \) satisfies the condition \( |f(x) - 1| < 0.2 \).

Thus, \( \delta \) is calculated as:
\[ \delta = 0.3 \]

**Conclusion:**
By analyzing the graph, \( \delta \) is determined to be 0.3. This ensures that within this interval, changes in \( x \) result in corresponding \( f(x) \) values that are close to 1 within a margin of 0.2.
Transcribed Image Text:**Title: Understanding Limits with Graphical Analysis** **Objective:** Use the given graph of the function \( f \) to determine a number \( \delta \) such that if \( |x - 1| < \delta \), then \( |f(x) - 1| < 0.2 \). **Graph Explanation:** The graph displays a curve representing the function \( f \). The x-axis is labeled \( x \) and the y-axis is labeled \( y \). Key points on the graph: - The curve \( f \) passes through key y-values at 1.2 and 0.8. - Horizontal lines span these y-values to indicate the possible values for \( f(x) \) that are within 0.2 units of 1. - Vertical lines highlight the corresponding x-values on the graph centered around \( x = 1 \). - Specifically, the vertical lines demarcate the interval \( x = 0.7 \) and \( x = 1.1 \). **Task:** Identify \( \delta \) by observing where the lines parallel to \( y = 1 \) intersect the curve \( f \). You should determine \( \delta \) such that \( |x - 1| < \delta \) implies \( 0.8 < f(x) < 1.2 \). **Solution:** From the graph, we can observe that for the interval \( 0.7 < x < 1.1 \), the function \( f(x) \) satisfies the condition \( |f(x) - 1| < 0.2 \). Thus, \( \delta \) is calculated as: \[ \delta = 0.3 \] **Conclusion:** By analyzing the graph, \( \delta \) is determined to be 0.3. This ensures that within this interval, changes in \( x \) result in corresponding \( f(x) \) values that are close to 1 within a margin of 0.2.
Expert Solution
Step 1

If x<k, then it can be written that: -k<x<k

We need to calculate δ such that if x-1<δ, then f(x)-1<0.2.

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