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Use the formula d = √²+r₂²-2rr₂ cos (0₁-0₂) to find the distance between the two points indicated in polar coordinates. (3, π/6) and (2, π/3)

Use the formula d = √²+r₂²-2rr₂ cos (0₁-0₂) to find the distance between the two points indicated in polar coordinates. (3, π/6) and (2, π/3)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The text provides a formula for calculating the distance between two points in polar coordinates. The formula is: \[ d = \sqrt{r_1^2 + r_2^2 - 2r_1r_2 \cos(\theta_1 - \theta_2)} \] This formula is used to find the distance between the two points given in polar coordinates: - Point 1: (3, π/6) - Point 2: (2, π/3) To apply the formula, substitute the values for \( r_1 = 3 \), \( r_2 = 2 \), \( \theta_1 = \pi/6 \), and \( \theta_2 = \pi/3 \) into the equation.
Transcribed Image Text:The text provides a formula for calculating the distance between two points in polar coordinates. The formula is: \[ d = \sqrt{r_1^2 + r_2^2 - 2r_1r_2 \cos(\theta_1 - \theta_2)} \] This formula is used to find the distance between the two points given in polar coordinates: - Point 1: (3, π/6) - Point 2: (2, π/3) To apply the formula, substitute the values for \( r_1 = 3 \), \( r_2 = 2 \), \( \theta_1 = \pi/6 \), and \( \theta_2 = \pi/3 \) into the equation.
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