Use the following theoretical equation A2B3 + 3 C2D --> A2D3 + 3 C2B Calculate the number of molecules of C2B formed from the reaction of (8.0000x10^1) grams of A2B3 and (1.170x10^2) grams of C2D The atomic weight of A is 15.0 grams/mol The atomic weight of B is 50.0 grams/mol The atomic weight of C is 35.0 grams/mol The atomic weight of D is 120.0 grams/mol Avogadro's number is (6.02200x10^23)

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Q: Consider the following hypothetical equation.  A2B3 +  3 C2D --> A2D3 + 3 C2B OR A2 B3 + 3 C2 D…

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Q: Consider the following hypothetical equation.  2 AB3 +  3 C2D --> A2D3 + 6 CB OR 2 A B3 + 3 C2 D…

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Q: U + 3 Br2 →  UBr6            What is my actual yield of uranium hexabromide if I start with 100…

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Q: Consider the following hypothetical equation.  A2B3 +  3 C2D --> A2D3 + 3 C2B OR A2 B3 + 3 C2 D…

A: We have to find the theoretical yield

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Q: Calculate the theoretical yield of A2D3 produced

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Q: Use the following theoretical equation AB2 + 2 C --> 2 CB +  A (OR A B2 + 2 C right arrow 2 C B +…

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Q: 3 A2B + 6 CD --> 6 AD + 3 C2B (OR 3 A2 B + 6 C D right arrow 6 A D + 3 C2 B) Calculate the number…

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Q: How much would 2.4 x 1024 molecules of N2O5 weigh?

A: Moles=2.4*10^24/(6.022*10^23) = 4

Q: Consider the following hypothetical equation.  2 AB3 +  3 C2D --> A2D3 + 6 CB OR 2 A B3 + 3 C2 D…

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Q: Consider the following hypothetical equation.  A2B3 +  3 C2D --> A2D3 + 3 C2B OR A2 B3 + 3 C2 D…

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Q: Calculate the number of atoms in each of the element in 1.0253 g of glucose, C6H12O6.

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Q: Consider the following hypothetical equation.  A2B3 +  3 C2D --> A2D3 + 3 C2B OR A2 B3 + 3 C2 D…

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Q: Consider the following hypothetical equation.  A2B3 +  3 C2D --> A2D3 + 3 C2B OR A2 B3 + 3 C2 D…

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Q: How many moles are present in a (3.3x10^0) mg sample of calcium?

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Q: and

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Q: Consider the following hypothetical equation.  2 AB3 +  3 C2D --> A2D3 + 6 CB OR 2 A B3 + 3 C2 D…

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Q: Calculate the number of molecules of C2B formed

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.