Use the following information to determine the standard enthalpy change when 1.00 mol of PbO(s) is formed from lead metal and excess oxygen gas by the reaction 2Pb(s) + O2(g) PbO(s) .... PbO(s) + C(graphite) -Pb(s) +AH° = 107 kJ CO(g) %3D 2C(graphite) + O2(g) -2CO(g) AH° = -222 kJ %3D Select one: a. -115 kJ b. -218 kJ О с. - 436 kJ d. -329 kJ e. +436 kJ

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Use the following information to determine the standard enthalpy
change when 1.00 mol of PbO(s) is formed from lead metal and
excess oxygen gas by the reaction
2Pb(s) + O2(g) PbO(s)
PbO(s) + C(graphite) -Pb(s) +AH° = 107 kJ
Co(g)
2C(graphite) + O2(g) -2CO(g) AH° = -222 kJ
Select one:
a. -115 kJ
b. -218 kJ
C. - 436 kJ
d. -329 kJ
e. +436 kJ
Transcribed Image Text:Use the following information to determine the standard enthalpy change when 1.00 mol of PbO(s) is formed from lead metal and excess oxygen gas by the reaction 2Pb(s) + O2(g) PbO(s) PbO(s) + C(graphite) -Pb(s) +AH° = 107 kJ Co(g) 2C(graphite) + O2(g) -2CO(g) AH° = -222 kJ Select one: a. -115 kJ b. -218 kJ C. - 436 kJ d. -329 kJ e. +436 kJ
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