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Use the following data to estimate the value of AH rxn for the represented process? HINT: use the slope to calculate ASrxn. Use ASrxn and any value of AGrxn from the plot to calculate AHrxn a b с d -75 kJ -50 kJ 0 kJ AG (kJ) 50 kJ 35 30 25 20 15 10 5 Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. 0 200 250 Temperature (K) ● 300 350 O 400

Use the following data to estimate the value of AH rxn for the represented process? HINT: use the slope to calculate ASrxn. Use ASrxn and any value of AGrxn from the plot to calculate AHrxn a b с d -75 kJ -50 kJ 0 kJ AG (kJ) 50 kJ 35 30 25 20 15 10 5 Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. 0 200 250 Temperature (K) ● 300 350 O 400

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Use the following data to estimate the value of AH rxn for the represented process? HINT: use the slope to calculate ASrxn. Use ASrxn and any value of AGrxn from the plot to calculate AHrxn a b C d -75 kJ -50 kJ 0 kJ AG (kJ) 50 kJ 35 30 25 20 15 10 5 Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. 0 200 250 Temperature (K) ● 300 350 O 400
Transcribed Image Text:Use the following data to estimate the value of AH rxn for the represented process? HINT: use the slope to calculate ASrxn. Use ASrxn and any value of AGrxn from the plot to calculate AHrxn a b C d -75 kJ -50 kJ 0 kJ AG (kJ) 50 kJ 35 30 25 20 15 10 5 Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. 0 200 250 Temperature (K) ● 300 350 O 400
Expert Solution
Step 1: Slope of graph



The slope of the graph can be calculated using the following formula:


```

slope = (y2 - y1) / (x2 - x1)

```


where


* y is the value of ΔG at temperature x

* x is the temperature


In this case, the points on the graph are (250, 0 kJ) and (300, 15 kJ). So, the slope is:


```

slope = (0 kJ - 15 kJ) / (250 K - 300 K) = -0.30 kJ/K

```


The negative value of the slope indicates that ΔG decreases with increasing temperature, as expected for an exothermic reaction.



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