Use the following data to estimate AH; for potassium bromide. 1 K(s) + Br2 (g) KBr(s) Lattice energy -671 kJ/mol Ionization energy for K 419 kJ/mol Electron affinity of Br -325 kJ/mol Bond energy of Br2 193 kJ/mol Enthalpy of sublimation for K 90. kJ/mol AH = kJ/mol %3D

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**Estimating the Enthalpy Change of Formation (\( \Delta H_f^\circ \)) for Potassium Bromide**

Use the following data to estimate \( \Delta H_f^\circ \) for potassium bromide:

\[ \text{K(s)} + \frac{1}{2} \text{Br}_2(g) \rightarrow \text{KBr(s)} \]

### Given Data:
- **Lattice energy**: \(-671 \, \text{kJ/mol}\)
- **Ionization energy for K**: \(419 \, \text{kJ/mol}\)
- **Electron affinity of Br**: \(-325 \, \text{kJ/mol}\)
- **Bond energy of Br}_2\)**: \(193 \, \text{kJ/mol}\)
- **Enthalpy of sublimation for K**: \(90. \, \text{kJ/mol}\)

### Objective:
Calculate the standard enthalpy change of formation, \( \Delta H_f^\circ \), in kJ/mol.
Transcribed Image Text:**Estimating the Enthalpy Change of Formation (\( \Delta H_f^\circ \)) for Potassium Bromide** Use the following data to estimate \( \Delta H_f^\circ \) for potassium bromide: \[ \text{K(s)} + \frac{1}{2} \text{Br}_2(g) \rightarrow \text{KBr(s)} \] ### Given Data: - **Lattice energy**: \(-671 \, \text{kJ/mol}\) - **Ionization energy for K**: \(419 \, \text{kJ/mol}\) - **Electron affinity of Br**: \(-325 \, \text{kJ/mol}\) - **Bond energy of Br}_2\)**: \(193 \, \text{kJ/mol}\) - **Enthalpy of sublimation for K**: \(90. \, \text{kJ/mol}\) ### Objective: Calculate the standard enthalpy change of formation, \( \Delta H_f^\circ \), in kJ/mol.
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