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Use the following constants if necessary. Coulomb constant, k = 8.987 x 10º N · m² /Cacuum permitivity, €o = 8.854 × 10-12 F/m. Magnetic Permeability of vacuum, lo = 12.566370614356 × 10-7 H/m. Magnitude of the Charge of one electron, e = -1.60217662 × 10-19 CMass of one electron, me = 9.10938356 × 10-31 kgUnless specified otherwise, each symbol carries their usual meaning. For example, µCmeans micro coulomb The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core with radius r1 = 10 mmand outer hollow conducting tube with an inner radius of r, = 39 mmThe length of the capacitor is L= 21 cm. Fiqure 2 is the cross sectional view of the system. This system of rod and shell is connected to a voltage source of emf E = 5.6 volts. There is no dielectric material present in the system as of now. PartI a)Calculate the capacitance of this capacitor. capacitance Give your answer up to at least three significance digits. F b)Say the inner rod is negativelycharged. Given this, calculate the charge density of the outer surface. And show how the electric field lines are oriented in this system. Hint: you can use the cross section for this (Fig. 2). charge density of the outer surface Give your answer up to at least three significance digits. C/m? Note Following two parts of this questions are independent of each other. You need to consider each part sequentially connected to part (I) only. That is,

Use the following constants if necessary. Coulomb constant, k = 8.987 x 10º N · m² /Cacuum permitivity, €o = 8.854 × 10-12 F/m. Magnetic Permeability of vacuum, lo = 12.566370614356 × 10-7 H/m. Magnitude of the Charge of one electron, e = -1.60217662 × 10-19 CMass of one electron, me = 9.10938356 × 10-31 kgUnless specified otherwise, each symbol carries their usual meaning. For example, µCmeans micro coulomb The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core with radius r1 = 10 mmand outer hollow conducting tube with an inner radius of r, = 39 mmThe length of the capacitor is L= 21 cm. Fiqure 2 is the cross sectional view of the system. This system of rod and shell is connected to a voltage source of emf E = 5.6 volts. There is no dielectric material present in the system as of now. PartI a)Calculate the capacitance of this capacitor. capacitance Give your answer up to at least three significance digits. F b)Say the inner rod is negativelycharged. Given this, calculate the charge density of the outer surface. And show how the electric field lines are oriented in this system. Hint: you can use the cross section for this (Fig. 2). charge density of the outer surface Give your answer up to at least three significance digits. C/m? Note Following two parts of this questions are independent of each other. You need to consider each part sequentially connected to part (I) only. That is,

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Note Following two parts of this questions are independent of each other. You need to consider each part sequentially connected to part (I) only. That is, sequence 1 -> part (I) then part (II) sequence 2 -> part (I) then part (II) PartII Right after part (I). c) The battery remains connected to the capacitor and we insert a dielectric material between the rod and shell, replacing air completely. The dielectric constant of the material is k = 4.4 At this point, calculate the total energy stored in the capacitor. total energy stored. Give your answer up to at least three significance digits. PartIII Right after part (1). d)We disconnect the battery from the capacitor and then we insert a dielectric material between the rod and shell, replacing air completely. The dielectric constant of the material is k as before. Now, how much energy is stored in the capacitor? Are the answers of (c) and (d) different from each other? Briefly explain the reason. energy stored Give your answer up to at least three significance digits. Submit You have used 0 of 20 attempts Save
Transcribed Image Text:Note Following two parts of this questions are independent of each other. You need to consider each part sequentially connected to part (I) only. That is, sequence 1 -> part (I) then part (II) sequence 2 -> part (I) then part (II) PartII Right after part (I). c) The battery remains connected to the capacitor and we insert a dielectric material between the rod and shell, replacing air completely. The dielectric constant of the material is k = 4.4 At this point, calculate the total energy stored in the capacitor. total energy stored. Give your answer up to at least three significance digits. PartIII Right after part (1). d)We disconnect the battery from the capacitor and then we insert a dielectric material between the rod and shell, replacing air completely. The dielectric constant of the material is k as before. Now, how much energy is stored in the capacitor? Are the answers of (c) and (d) different from each other? Briefly explain the reason. energy stored Give your answer up to at least three significance digits. Submit You have used 0 of 20 attempts Save
Use the following constants if necessary. Coulomb constant, k = 8.987 x 10º N · m² /Cacuum permitivity, €o = 8.854 × 10-12 F/m. Magnetic Permeability of vacuum, lo = 12.566370614356 × 10-7 H/m. Magnitude of the Charge of one electron, e = -1.60217662 × 10-19 CMass of one electron, me = 9.10938356 × 10-31 kgUnless specified otherwise, each symbol carries their usual meaning. For example, µCmeans micro coulomb The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core with radius r1 = 10 mmand outer hollow conducting tube with an inner radius of r, = 39 mmThe length of the capacitor is L= 21 cm. Fiqure 2 is the cross sectional view of the system. This system of rod and shell is connected to a voltage source of emf E = 5.6 volts. There is no dielectric material present in the system as of now. PartI a)Calculate the capacitance of this capacitor. capacitance Give your answer up to at least three significance digits. F b)Say the inner rod is negativelycharged. Given this, calculate the charge density of the outer surface. And show how the electric field lines are oriented in this system. Hint: you can use the cross section for this (Fig. 2). charge density of the outer surface Give your answer up to at least three significance digits. C/m? Note Following two parts of this questions are independent of each other. You need to consider each part sequentially connected to part (I) only. That is,
Transcribed Image Text:Use the following constants if necessary. Coulomb constant, k = 8.987 x 10º N · m² /Cacuum permitivity, €o = 8.854 × 10-12 F/m. Magnetic Permeability of vacuum, lo = 12.566370614356 × 10-7 H/m. Magnitude of the Charge of one electron, e = -1.60217662 × 10-19 CMass of one electron, me = 9.10938356 × 10-31 kgUnless specified otherwise, each symbol carries their usual meaning. For example, µCmeans micro coulomb The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core with radius r1 = 10 mmand outer hollow conducting tube with an inner radius of r, = 39 mmThe length of the capacitor is L= 21 cm. Fiqure 2 is the cross sectional view of the system. This system of rod and shell is connected to a voltage source of emf E = 5.6 volts. There is no dielectric material present in the system as of now. PartI a)Calculate the capacitance of this capacitor. capacitance Give your answer up to at least three significance digits. F b)Say the inner rod is negativelycharged. Given this, calculate the charge density of the outer surface. And show how the electric field lines are oriented in this system. Hint: you can use the cross section for this (Fig. 2). charge density of the outer surface Give your answer up to at least three significance digits. C/m? Note Following two parts of this questions are independent of each other. You need to consider each part sequentially connected to part (I) only. That is,
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