Use the following constants if necessary. Coulomb constant, k = 8.987 × 10° N - m² /C2. Vacuum permitivity, €o = 8.854 x 10-12 F/m. MagneticPermeability of vacuum, lo = 12.566370614356 x 10-7 H/m. Magnitude of the Charge of one electron, e = -1.60217662 × 10-19 C. Mass of oneelectron, me = 9.10938356 x 10-31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, µC means micro coulombObserver(A) is in a stationary frame S and anoher ovserver(B) in frame S' moving along +x axis from S frame. A measures the duration between twoevents in S frame be 10 seconds. What is the duration of the two events as measured by B in S' frame. Relative speed v = 0.4CTime measured iby BGive your answer up to at least three significance digits.Sec

Problem-based on the concept of time dilation; Let us consider the observer in the S frame, which…

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Use the following constants if necessary. Coulomb constant, k=8.987×109N⋅m2/C2. Vacuum permittivity, ϵ0=8.854×10−12F/m. Magnetic Permeability of vacuum, μ0=12.566370614356×10−7H/m. The magnitude of the Charge of one electron, e=−1.60217662×10−19C. Mass of one electron, me=9.10938356×10−31kg. Unless specified otherwise, each symbol carries its usual meaning. For example, μC means microcoulomb. PART -I Capacitors in the circuit have the capacitances C1=5.5μF, C2=4.4μF, C3=2.2μF, and C4=44μF and the emf of the battery is E=5V. a) Find the equivalent capacitance of the circuit. PART-II The capacitor in the first circuit C2 is replaced by the resistor R=11Ω in the second circuit. And a switch is placed as shown in the figure. The emf of the circuit is E=5V. Consider the capacitors are completely uncharged when the switch is open. b) Explain briefly what will happen - if we close the switch and connect to the P terminal of the circuit. Draw the circuit diagram. c) Calculate the time…
Find the force of electrical attraction between a proton and an electron that are 8.7 x 10-11 m apart. Compare this to the gravitational force between these particles. N Need Help? Read It Talk to a Tutor O vA 11:44 esc DII %23 $ & backspace 1 2 3 4 6 8 tab e t y a f enter shift V n m shift alt alt str)
Use the following constants if necessary. Coulomb constant, k = 8.987 × 10º N · m² /C¥acuum permitivity, en = 8.854 × 10-12 F/mMagnetic Permeability of vacuum, µo = 12.566370614356 × 10¬7 H/rMagnitude of the Charge of one electron, e = -1.60217662 x 10 1º CMass of one electron, me = 9.10938356 × 10 31 kgUnless specified otherwise, each symbol carries their usual meaning. For example, µCmeans micro coulomh Say you have 3 charges q1 = 24, q2 = 27, q3 = -26cated at (0, 13) (7, – 13)and (6, –20}espectively. Now, say you choose four random points on the xyplane denoted by p1 (0, 7) p2 (15, –16) p3 (-5, – 16ànd p4 (0, 13). Note that, all charges are in nano coulombs. And all coordinates are in centimeters. Given this information, answer the following questions: a)Calculate the relative position vector that points from p4 to q2. x component of the vector Give your answer up to at least three significance digits. m y component of the vector Give your answer up to at least three significance…
A point charge for which Q = 4.2 × 10-16 C and m = 2.5 x 10-26 kg is moving in the combined fields E = 250ax + 115ay - 230a, V/m and B = 2ax - ay - 3a, mT. If the charge velocity at t = 0 is v(0) = (2ax + 4ay +3az) × 105 m/s: %3D give the unit vector showing the direction in which the charge is accelerating at t = 0. find the kinetic energy of the charge at t = 0. Answers: a. Blank 1ax + Blank 2ay + Blank 3 az b. Blank 4 fJ
F=0.8975r^-2.00 And re-writing it as: (4)F=0.8975/r^-2.00 We can now compare it with Coulomb’s equation: (1)F=K|q1q2|/r^2 So, comparing these equations (4) and (1) we realize that: k=|q1q2|=0.8975 Plugging in values for charges: q1 = -10µC, and q2 = 10µC, isolating k (Coulomb’s constant), and recalling that 1µC = 10-6 C, we get: k|-10µC*10µC|=0.8975 k=0.8934/|-10µC*10µC|= 0.8934/10*10^-6C*10*10^-6C (3) Use this Example calculation above, and the trendline equation (3) coefficients that you have obtained on your graph, to find k. Show your work below. Be careful with powers of ten. k= 0.8975/|-10µC*10µC|= 0.8975/10*10^-6C*10*10^-6C = (5) Now, important part in reporting the answer is properly showing its units. To derive the SI units for Coulomb’s constant k, let’s look again at the equation (1), and re-write it as: k=F*r^2/|q1q2| (6) Recalling the units for all parameters in this equation: Force, F – Newtons, [N] Distance, r –…