Use the equation that follows for parts (a) and (b) below. Molecular masses are under each salt/molecule. Al2O3 (s) + 6 NaOH (4 + 6 HF (g)→ 2 NasAlF6 (s) + 6 H2O (g) 101.96 40.00 20.01 209.95 18.02 Part a) How many grams of aluminum oxide are needed to react with 3.5 L of HF at 305 K, 4.2 atm w w pressure in the presence of excess NaOH? wwwwm Part b). How much energy is released from the reaction of 56.0 g of HF? Assume that H for the reaction is -345 kJ.
Use the equation that follows for parts (a) and (b) below. Molecular masses are under each salt/molecule. Al2O3 (s) + 6 NaOH (4 + 6 HF (g)→ 2 NasAlF6 (s) + 6 H2O (g) 101.96 40.00 20.01 209.95 18.02 Part a) How many grams of aluminum oxide are needed to react with 3.5 L of HF at 305 K, 4.2 atm w w pressure in the presence of excess NaOH? wwwwm Part b). How much energy is released from the reaction of 56.0 g of HF? Assume that H for the reaction is -345 kJ.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Use the equation that follows for parts (a) and (b) below. Molecular masses are under each salt/molecule.
\[
\text{Al}_2\text{O}_3 (s) + 6 \text{NaOH} (l) + 6 \text{HF} (g) \rightarrow 2 \text{Na}_3\text{AlF}_6 (s) + 6 \text{H}_2\text{O} (g)
\]
\[
101.96 \quad 40.00 \quad 20.01 \quad 209.95 \quad 18.02
\]
Part a) How many grams of aluminum oxide are needed to react with 3.5 L of HF at 305 K, 4.2 atm pressure in the presence of excess NaOH?
Part b) How much energy is released from the reaction of 56.0 g of HF? Assume that \(\Delta H\) for the reaction is -345 kJ.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb73fd08b-4071-4726-b0d1-d357287a66bd%2Ffcb00eae-0df5-4d1c-8e64-2ee4ab337b35%2F8sgau2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use the equation that follows for parts (a) and (b) below. Molecular masses are under each salt/molecule.
\[
\text{Al}_2\text{O}_3 (s) + 6 \text{NaOH} (l) + 6 \text{HF} (g) \rightarrow 2 \text{Na}_3\text{AlF}_6 (s) + 6 \text{H}_2\text{O} (g)
\]
\[
101.96 \quad 40.00 \quad 20.01 \quad 209.95 \quad 18.02
\]
Part a) How many grams of aluminum oxide are needed to react with 3.5 L of HF at 305 K, 4.2 atm pressure in the presence of excess NaOH?
Part b) How much energy is released from the reaction of 56.0 g of HF? Assume that \(\Delta H\) for the reaction is -345 kJ.
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