Use the equation below to determine the limiting reactant. Mg (s) + 2 HC1 (aq) → MgCl, (aq) + H2 (g) When 6 moles of Mg is reacted with 6 moles of HCl, what is the limiting reactant?

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Use the equation below to determine the limiting reactant.
Mg (s) + 2 HC1 (aq) → MgCl, (aq) + H2 (g)
When 6 moles of Mg is reacted with 6 moles of HCl, what is the limiting reactant?
Transcribed Image Text:Use the equation below to determine the limiting reactant. Mg (s) + 2 HC1 (aq) → MgCl, (aq) + H2 (g) When 6 moles of Mg is reacted with 6 moles of HCl, what is the limiting reactant?
Mg because you will have 0 moles of Mg and 3 moles of HCl left over
HCl because you will have 3 moles of HCl left over and 0 moles Mg
HCl because you will have 0 moles of HCl and 3 moles of Mg left over
Mg because you will have 3 moles of Mg and 0 moles HCi
Transcribed Image Text:Mg because you will have 0 moles of Mg and 3 moles of HCl left over HCl because you will have 3 moles of HCl left over and 0 moles Mg HCl because you will have 0 moles of HCl and 3 moles of Mg left over Mg because you will have 3 moles of Mg and 0 moles HCi
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