Use the equation 6KI (aq) + 8HNO3 (aq)→6KNO3 (aq) + 2NO (g) + 312 (s) + 4H20 (1). If 27.00 mL of 0.81900 M potassium iodide react with 37.00 mL of 0.20700 M nitric acid, how many grams of solid iodine will be produced?
Use the equation 6KI (aq) + 8HNO3 (aq)→6KNO3 (aq) + 2NO (g) + 312 (s) + 4H20 (1). If 27.00 mL of 0.81900 M potassium iodide react with 37.00 mL of 0.20700 M nitric acid, how many grams of solid iodine will be produced?
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![Use the equation 6KI (aq) + 8HNO3 (aq)→ 6KNO3 (aq) + 2NO (g) + 312 (s) + 4H20 (1).
If 27.00 mL of 0.81900 M potassium iodide react with 37.00 mL of 0.20700 M nitric acid, how many
grams of solid iodine will be produced?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a17161d-5faf-453e-a286-cadca355b5e1%2F2dea65d1-6e85-4b77-baad-f549707e8552%2F0qm8u1r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use the equation 6KI (aq) + 8HNO3 (aq)→ 6KNO3 (aq) + 2NO (g) + 312 (s) + 4H20 (1).
If 27.00 mL of 0.81900 M potassium iodide react with 37.00 mL of 0.20700 M nitric acid, how many
grams of solid iodine will be produced?
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