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Use the dilution equation to calculate the number of milliliters of 3.00 M NaCl needed to make 600.0 mL of a saline solution with a final sodium chloride concentration of 0,154 M. Show your work. Use Civ= C2V2 set up table solve Er unknouh.

Use the dilution equation to calculate the number of milliliters of 3.00 M NaCl needed to make 600.0 mL of a saline solution with a final sodium chloride concentration of 0,154 M. Show your work. Use Civ= C2V2 set up table solve Er unknouh.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The handwritten text in the image reads: "Sufficient for maintenance of pH a NaCl solution is not a buffer. To maintain the pH buffer solution is required. PBS does not contain only NaCl." Below the handwriting, there is a printed exercise: "4. Use the dilution equation to calculate the number of milliliters of 3.00 M NaCl needed to make 600.0 mL of a saline solution with a final sodium chloride concentration of 0.154 M. Show your work: use C1V1 = C2V2 set up table solve for unknown." The handwritten notes for this problem are: "C1 = 3.00 M NaCl C2 = 0.154 M \[ V2 = 600.0 \, \text{mL} \] \[ V1 = \frac{(C2 \times V2)}{C1} \]" The solution is described through given concentrations and volumes, with the formula for dilution \( C1V1 = C2V2 \).
Transcribed Image Text:The handwritten text in the image reads: "Sufficient for maintenance of pH a NaCl solution is not a buffer. To maintain the pH buffer solution is required. PBS does not contain only NaCl." Below the handwriting, there is a printed exercise: "4. Use the dilution equation to calculate the number of milliliters of 3.00 M NaCl needed to make 600.0 mL of a saline solution with a final sodium chloride concentration of 0.154 M. Show your work: use C1V1 = C2V2 set up table solve for unknown." The handwritten notes for this problem are: "C1 = 3.00 M NaCl C2 = 0.154 M \[ V2 = 600.0 \, \text{mL} \] \[ V1 = \frac{(C2 \times V2)}{C1} \]" The solution is described through given concentrations and volumes, with the formula for dilution \( C1V1 = C2V2 \).
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