Use the data in the following table, which lists drive-thru order accuracy at popularfast food chains. Assume that orders are randomly selected from those included inthe table.Order AccurateOrder Not AccurateDrive-thru Restaurantс24134A32733B26360D14618If one order is selected, find the probability of getting food that is not fromRestaurant A.The probability of getting food that is not from Restaurant A is(Round to three decimal places as needed.)

Total number of orders in the table= 1122ABCDTotalOrder accurate327263241146977Order not…

Answered: Use the data in the following table,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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d. Find the p-value for the test. p-value=enter your response here (Round to three decimal places as needed.)
Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 1.50 and 2.25 Click to view page 1 of the table. Click to view page 2 of the table. Draw a sketch. Choose the correct graph below. O A. OB. Oc. z=1.50 z=2.25 z=1.50 z=2.25 z=1.50 z=2.25 The probability of getting a reading between 1.50°C and 2.25°C isO. (Round to four decimal places as needed.)
The data represent the results for a test for a certain disease. Assume one individual from the group is randomly selected. Find the probability of getting someone who tested positive, given that he or she had the disease. The probability is approximately (Round to three decimal places as needed.) View an example @ 2 s W S X 3 дв command # Get more help 26 80 F3 E D A GA C a R F tv % 5 V T G The individual actually had the disease O Yes No 135 Positive Negative 13 VAG 810 MacBook Air 6 B Y & 7 H F7 U 25 127 N * 8 DII 1 M ( 9 K O 0 I H qqqqqqqqı L A F10 Clear all P > л. : ; { + [ = Check answer I command option 11 18 ? F12 1 } 1 delete
Pl Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 0.50 and 2.00 Click to view page 1 of the table. Click to view page 2 of the table. Draw a sketch. Choose the correct graph below. OA. OB. О в. C. z-0.50 z-2.00 z-0.50 z-2.00 z-0.50 z-2.00 The probability of getting a reading between 0.50°C and 2.00°C is. Click to select your answer(s). atv 4 4. MacBook Air F10 F11 F9 F6 F7 F8 임미 F3 F5 F4 F2 F1 & %$4 4. #3 9- 6.
Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 1.50 and 2.25 Click to view page 1 of the table. Click to view page 2 of the table. Draw a sketch. Choose the correct graph below. O A. The probability of getting a reading between 1.50°C and 2.25°C is (Round to four decimal places as needed.) d Normal Table (Page 2) .00 Standard Normal (z) Distribution: Cumulative Area from the LEFT .5000 5398 5793 .6179 .6554 .6915 7257 .7580 7881 .8159 .8413 8643 .8849 .9032 9192 9332 9452 .9554 .9641 9713 9772 .9821 9861 0007 .01 5040 5438 5832 6217 .6591 z=1.50 z=2.25 6950 7291 .7611 7910 .8186 .8438 8665 8869 9049 9207 9345 9463 .9564 9649 .9719 9778 9826 9864 .02 5080 5478 5871 6255 6628 .6985 7324 7642 7939 .8212 8461 8686 8888 .9066 9222 9357 9474 .9573 9656…
Fill in the rest of the joint distribution so that X and Y are independent. There are two possible answers: Y 0 1 X=0 1 ? 2/9 2/9
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)

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