**Infection Rate Hypothesis Testing**A new virus has taken root in a country. Government officials are reporting that 9.4% of the population is currently infected with the virus. However, epidemiologists across the country claim to be observing a much higher infection rate.It was found that 171 people out of a randomly selected sample of 1490 people from around the country were infected with the virus.Use the critical value method to determine if the sample data support the epidemiologists’ supposition that the true rate of infection in the country is higher than 9.4%. Use a significance level of 5%.1. **State the null and alternative hypotheses for this test.** Null Hypothesis (\(H_0\)): \( p = 0.094 \) Alternative Hypothesis (\(H_1\)): \( p > 0.094 \)2. **Determine if this test is left-tailed, right-tailed, or two-tailed.** - two-tailed - right-tailed - left-tailed *Selected Option:* right-tailed3. **Should the standard normal (z) distribution or Student’s (t) distribution be used for this test?** - The standard normal (z) distribution should be used - The Student’s (t) distribution should be used *Selected Option:* The standard normal (z) distribution should be used ## Hypothesis Testing in Epidemiology### Determine the Critical Value(s)Determine the critical value(s) for this hypothesis test. Round the solution(s) to two decimal places. If more than one critical value exists, enter the solutions using a comma-separated list.`[Text Box]`### Determine the Test StatisticDetermine the test statistic. Round the solution to two decimal places.`[Text Box]`### Determine the Appropriate ConclusionDetermine the appropriate conclusion for this hypothesis test.- ⬜ The sample data provide sufficient evidence to reject the epidemiologists' claim (alternative hypothesis) that the infection rate is higher than 9.4% and thus we concluded that the infection rate of the virus is likely 9.4%.- ⬜ The sample data do not provide sufficient evidence to reject the government's claim (null hypothesis) that the infection rate of the virus is 9.4% and thus we conclude that the infection rate of the virus is likely 9.4%.- ⬜ The sample data provide sufficient evidence to reject the government's claim (null hypothesis) that the infection rate of the virus is 9.4% and thus we conclude that the infection rate of the virus is likely greater than 9.4%.- ⬜ The sample data do not provide sufficient evidence to reject the epidemiologists' claim (alternative hypothesis) that the infection rate is higher than 9.4% and thus we concluded that the infection rate of the virus is likely greater than 9.4%.### Additional Information- **Temperature:** 75°F- **Weather Condition:** Partly cloudy- **User Interface:** Screenshot shows a typical digital input interface for online educational materials.This information helps in understanding hypothesis testing's applications in real-world situations such as epidemiology. Complete the critical values and test statistics boxes before moving on to conclusion determination.

According to the given information in this question We need to answer the rest of the following

Answered: Use the critical value method to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
Use the departure delay times and the arrival delay times to test the claim that there is a correlation between departure delay times and arrival delay times. Test for rank correlation with a 0.05 significance level. Click here to view the flight delay data. Click here to view the critical values of Spearman's rank correlation coefficient. Flight delay data .... Determine the null and alternative hypotheses for this test. Choose the correct answer below. O A. Hg: Ps =0 Departure Delay Arrival Departure Delay Arrival O B. Ho: Ps #0 H: Ps = 0 Departure Delay Arrival H: Ps #0 Delay Delay Delay - 36 -7 11 14 OC. Ho:r 0 H:r=0 O D. Ho: r =0 H:rg 40 -21 15 25 -33 10 -32 Determine the the correlation coefficient. - 5 32 13 4 12 16 -23 (Round to three decimal places as needed.) 3 14 -38 60 28 13 3 13 149 111 Determine the critical value(s) of the correlation coefficient, -38 -7 -35 - 3 -21 -23 23 - 2 -10 14 (Round to three decimal places as needed. Use a comma to separate answers as needed.)…
8.42 Sample size needed for an evaluation. You are planning an evaluation of a semester-long alcohol awareness campaign at your college. Previous evaluations indicate that about 20% of the students surveyed will respond Yes to the question "Did the campaign alter your behavior toward alcohol consumption?" How large a sample of students should you take if you want the margin of error for 95% confidence to be about 0.07?
Using the results obtained for a study on website development below, how would we interpret the results of this hypothesis test? The claim is the percent of customers who abandon a web page due to long load times is different from 34%. The significance level is 0.10. The test statistic is 2.50. Select the correct answer below: Reject H0. There is strong evidence to conclude that the percent of customers who abandon a web page due to long load times is greater than 34%. Reject H0. There is NOT strong evidence to conclude that the percentage of customers who abandon a web page due to long load times is greater than 34%. Fail to reject H0. There is strong evidence to conclude that the percent of customers who abandon a web page due to long load times is greater than 34%. Fail to reject H0. There is NOT strong evidence to conclude that the percentage of customers who abandon a web page due to long load times is greater than 34%.
1 Jump to level 1 A pipes manufacturer makes pipes with a length that is supposed to be 11 inches. A quality control technician sampled 32 pipes and found that the sample mean length was 11.09 inches and the sample standard deviation was 0.2 inches. The technician claims that the mean pipe length is not 11 inches. What type of hypothesis test should be performed? Select What is the test statistic? Ex: 0.123 What is the number of degrees of freedom? Ex: 20 Does sufficient evidence exist at the a= 0.05 significance level to support the technician's claim? Select Check HIN 60°F
Use a y-test to test the claim o = 0.48 at the a = 0.01 significance level using sample statistics s = 0.466 and n = 15. Assume the population is normally distributed. Identify the null and alternative hypotheses. YA. Ho: o? = 0.48 O B. Ho: o 20.48 H:o +0.48 H,: o 0.48 Identify the test statistic. (Round to two decimal places as needed.)
In a study of the accuracy of fast food drive-through orders, one restaurant had 31 orders that were not accurate among 355 orders observed. Use a 0.10 significance level to test the claim that the rate of inaccurate orders is equal to 10%. Does the accuracy rate appear to be acceptable? Question content area bottom Part 1 Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. H0: p≠0.1 H1: p=0.1 B. H0: p=0.1 H1: p<0.1 C. H0: p=0.1 H1: p≠0.1 Your answer is correct. D. H0: p=0.1 H1: p>0.1 Part 2 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is negative 0.80−0.80. (Round to two decimal places as needed.) Part 3 Identify the P-value for this hypothesis test. The P-value for this hypothesis test is 0.4240.424. (Round to three decimal places as needed.) Part 4 Identify the conclusion for this hypothesis test.…
If you use a 0.05 level of significance in a two-tail hypothesis test, what decision will you make if ZSTAT = + 1.65? Click here to view page 1 of the cumulative standardized normal distribution table. Click here to view page 2 of the cumulative standardized normal distribution table. .... Determine the decision rule. Select the correct choice below and fill in the answer box(es) within your choice. (Round to two decimal places as needed.) O A. Reject H, if ZSTAT or ZSTAT> + O B. Reject H, if ZSTAT U
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In a study of the accuracy of fast food drive-through orders, one restaurant had 31 orders that were not accurate among 355 orders observed. Use a 0.10 significance level to test the claim that the rate of inaccurate orders is equal to 10%. Does the accuracy rate appear to be acceptable? Question content area bottom Part 1 Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. H0: p≠0.1 H1: p=0.1 B. H0: p=0.1 H1: p<0.1 C. H0: p=0.1 H1: p≠0.1 D. H0: p=0.1 H1: p>
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A poll asked whether states should be allowed to conduct random drug tests on elected officials. Of 21,327 respondents, 56% said "yes." a. Determine the margin of error for a 99% confidence interval. b. Without doing any calculations, indicate whether the margin of error is larger or smaller for a 90% confidence interval. Explain your answer. Click here to view page 1 of the table of areas under the standard normal curve. Click here to view page 2 of the table of areas under the standard normal curve. a. The margin of error for a 99% confidence interval is (Round to three decimal places as needed.) b. Without doing any calculations, indicate whether the margin of error is larger or smaller for a 90% confidence interval. A. The margin of error will be smaller for a 90% confidence interval. B. The margin of error will be about the same for a 90% confidence interval. C. The margin of error will be larger for a 90% confidence interval. D. There is insufficient information to determine the…

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