Use the chemical equation and the table to answer the question. Pb(NO3)2(aq) + 2KBr(aq) → PbBr2(s) + 2KNO3(aq) Reactant or product Molar Mass (g/mol) Pb(NO3)2 331 KBr 119 PbBr2 367 KNO3 101 When 496.5 grams of Pb(NO3)2 reacts completely with KBr, how much will the total mass of the products be? 550.5 g 702.0 g 496.5 g 853.5 g
Use the chemical equation and the table to answer the question. Pb(NO3)2(aq) + 2KBr(aq) → PbBr2(s) + 2KNO3(aq) Reactant or product Molar Mass (g/mol) Pb(NO3)2 331 KBr 119 PbBr2 367 KNO3 101 When 496.5 grams of Pb(NO3)2 reacts completely with KBr, how much will the total mass of the products be? 550.5 g 702.0 g 496.5 g 853.5 g
General, Organic, and Biological Chemistry
7th Edition
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:H. Stephen Stoker
Chapter6: Chemical Calculations: Formula Masses, Moles, And Chemical Equations
Section: Chapter Questions
Problem 6.66EP: For the chemical reaction C3H8O2+4O23CO2+4H2O how many product molecules are formed when nine C3H8O2...
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Use the chemical equation and the table to answer the question.
Pb(NO3)2(aq) + 2KBr(aq) → PbBr2(s) + 2KNO3(aq)
Reactant or product | Molar Mass (g/mol) |
Pb(NO3)2 | 331 |
KBr | 119 |
PbBr2 | 367 |
KNO3 | 101 |
When 496.5 grams of Pb(NO3)2 reacts completely with KBr, how much will the total mass of the products be?
- 550.5 g
- 702.0 g
- 496.5 g
- 853.5 g
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