Use the Chain Rule to evaluate the partial derivative at the point (r, 0) = (2√√2, 4), where g(x, y) = x+1²,2 y = 7r sin(0). (Use symbolic notation and fractions where needed.) dg де (r.0) = , x = 8r cos(0),

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter9: Multivariable Calculus
Section9.CR: Chapter 9 Review
Problem 12CR
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**Problem Description:**

Use the Chain Rule to evaluate the partial derivative \(\frac{\partial g}{\partial \theta}\) at the point \((r, \theta) = \left( 2\sqrt{2}, \frac{\pi}{4} \right)\), where \(g(x, y) = \frac{1}{x + y^2}\), \(x = 8r \cos(\theta)\), and \(y = 7r \sin(\theta)\).

(Use symbolic notation and fractions where needed.)

\[
\left. \frac{\partial g}{\partial \theta} \right|_{(r, \theta)} = \text{[Answer box]}
\]
Transcribed Image Text:**Problem Description:** Use the Chain Rule to evaluate the partial derivative \(\frac{\partial g}{\partial \theta}\) at the point \((r, \theta) = \left( 2\sqrt{2}, \frac{\pi}{4} \right)\), where \(g(x, y) = \frac{1}{x + y^2}\), \(x = 8r \cos(\theta)\), and \(y = 7r \sin(\theta)\). (Use symbolic notation and fractions where needed.) \[ \left. \frac{\partial g}{\partial \theta} \right|_{(r, \theta)} = \text{[Answer box]} \]
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