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Use superposition to solve for i, and v, in the circuit in Fig. P4.93. Figure P4.93 + 30 Ω 135 V vo + 40 Ω ww 18 A 60 Ω io 20 Ω • 80 Ω Σ25 Ω

Use superposition to solve for i, and v, in the circuit in Fig. P4.93. Figure P4.93 + 30 Ω 135 V vo + 40 Ω ww 18 A 60 Ω io 20 Ω • 80 Ω Σ25 Ω

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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### Electrical Engineering Problem: Using Superposition to Solve Circuits In this example problem, we are tasked with using the principle of superposition to determine the values of \( i_o \) and \( v_o \) in the given circuit, which is depicted in **Figure P4.93**. #### Given Data in Figure P4.93: - A 135 V voltage source in series with a 30 Ω resistor. - An 18 A current source. - Resistors with the following values: - 40 Ω - 60 Ω - 20 Ω - 80 Ω - 25 Ω #### Explanation of the Circuit Diagram: - The circuit includes both a voltage source and a current source. - The 135 V voltage source is in series with a 30 Ω resistor on the left side. - The 18 A current source is placed in the middle, with its positive terminal facing up. - There is a 40 Ω resistor in series with the current source along the top path. - There are parallel branches with resistors values of 60 Ω, 80 Ω, and 25 Ω, forming the bottom paths. - A 20 Ω resistor is located in the upper right branch of the circuit. The circuit also provides: - \( v_o \) is the voltage across the 60 Ω resistor. - \( i_o \) is the current through the 40 Ω resistor. ### Steps to Use Superposition: 1. **Deactivate All Sources Except One**: Temporarily deactivate all but one source (one at a time) to simplify the circuit and calculate the contribution of each source to the overall current or voltage. - To deactivate a voltage source, replace it with a short circuit. - To deactivate a current source, replace it with an open circuit. 2. **Analyze the Modified Circuit**: Solve the revised simpler circuits using standard circuit analysis techniques (Ohm’s Law, Kirchhoff’s Current Law, Kirchhoff’s Voltage Law, etc.). 3. **Combine Results**: Once the contributions from each source are determined separately, sum them to find the overall values of \( i_o \) and \( v_o \). By following these steps and using superposition, you can determine the current \( i_o \) through the 40 Ω resistor and the voltage \( v_o \) across the 60 Ω resistor in the circuit shown in Figure P4.93. This method
Transcribed Image Text:### Electrical Engineering Problem: Using Superposition to Solve Circuits In this example problem, we are tasked with using the principle of superposition to determine the values of \( i_o \) and \( v_o \) in the given circuit, which is depicted in **Figure P4.93**. #### Given Data in Figure P4.93: - A 135 V voltage source in series with a 30 Ω resistor. - An 18 A current source. - Resistors with the following values: - 40 Ω - 60 Ω - 20 Ω - 80 Ω - 25 Ω #### Explanation of the Circuit Diagram: - The circuit includes both a voltage source and a current source. - The 135 V voltage source is in series with a 30 Ω resistor on the left side. - The 18 A current source is placed in the middle, with its positive terminal facing up. - There is a 40 Ω resistor in series with the current source along the top path. - There are parallel branches with resistors values of 60 Ω, 80 Ω, and 25 Ω, forming the bottom paths. - A 20 Ω resistor is located in the upper right branch of the circuit. The circuit also provides: - \( v_o \) is the voltage across the 60 Ω resistor. - \( i_o \) is the current through the 40 Ω resistor. ### Steps to Use Superposition: 1. **Deactivate All Sources Except One**: Temporarily deactivate all but one source (one at a time) to simplify the circuit and calculate the contribution of each source to the overall current or voltage. - To deactivate a voltage source, replace it with a short circuit. - To deactivate a current source, replace it with an open circuit. 2. **Analyze the Modified Circuit**: Solve the revised simpler circuits using standard circuit analysis techniques (Ohm’s Law, Kirchhoff’s Current Law, Kirchhoff’s Voltage Law, etc.). 3. **Combine Results**: Once the contributions from each source are determined separately, sum them to find the overall values of \( i_o \) and \( v_o \). By following these steps and using superposition, you can determine the current \( i_o \) through the 40 Ω resistor and the voltage \( v_o \) across the 60 Ω resistor in the circuit shown in Figure P4.93. This method
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