'Use Stokes' Theorem to compute | 1 F. dr where C is the curve where the cylinder a? + y? = 1 intersects the plane z = 1, given that curl F = (xz, –yz, r² + y²).

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Assignment: Applying Stokes' Theorem

**Task Description:**

Use Stokes' Theorem to compute the line integral

\[ \oint_C \mathbf{F} \cdot d\mathbf{r} \]

where \(C\) is the curve formed by the intersection of the cylinder \(x^2 + y^2 = 1\) and the plane \(z = 1\). You are given that the curl of \(\mathbf{F}\) is:

\[ \text{curl} \, \mathbf{F} = \langle xz, -yz, x^2 + y^2 \rangle. \]

**Background:**

Stokes' Theorem relates a surface integral of the curl of a vector field over a surface \(\Sigma\) to the line integral of the vector field over its boundary curve \(C\):

\[ \oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_{\Sigma} (\nabla \times \mathbf{F}) \cdot d\mathbf{S} \]

Here, \(\nabla \times \mathbf{F}\) denotes the curl of \(\mathbf{F}\), and \(d\mathbf{S}\) is the vector area element of the surface \(\Sigma\).

**Instructions:**

1. Recognize the curve \(C\) formed by the intersection of the cylinder \(x^2 + y^2 = 1\) and the plane \(z = 1\).
2. Identify the surface \(\Sigma\) with boundary \(C\).
3. Compute the surface integral using the given curl of \(\mathbf{F}\).

**Key Points:**

- The curve \(C\) is a circle of radius 1 in the plane \(z = 1\).
- The surface \(\Sigma\) can be taken as the planar disk \(x^2 + y^2 \leq 1\) at \(z = 1\).

Below is the detailed solution to guide you through each step.

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Transcribed Image Text:--- ### Assignment: Applying Stokes' Theorem **Task Description:** Use Stokes' Theorem to compute the line integral \[ \oint_C \mathbf{F} \cdot d\mathbf{r} \] where \(C\) is the curve formed by the intersection of the cylinder \(x^2 + y^2 = 1\) and the plane \(z = 1\). You are given that the curl of \(\mathbf{F}\) is: \[ \text{curl} \, \mathbf{F} = \langle xz, -yz, x^2 + y^2 \rangle. \] **Background:** Stokes' Theorem relates a surface integral of the curl of a vector field over a surface \(\Sigma\) to the line integral of the vector field over its boundary curve \(C\): \[ \oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_{\Sigma} (\nabla \times \mathbf{F}) \cdot d\mathbf{S} \] Here, \(\nabla \times \mathbf{F}\) denotes the curl of \(\mathbf{F}\), and \(d\mathbf{S}\) is the vector area element of the surface \(\Sigma\). **Instructions:** 1. Recognize the curve \(C\) formed by the intersection of the cylinder \(x^2 + y^2 = 1\) and the plane \(z = 1\). 2. Identify the surface \(\Sigma\) with boundary \(C\). 3. Compute the surface integral using the given curl of \(\mathbf{F}\). **Key Points:** - The curve \(C\) is a circle of radius 1 in the plane \(z = 1\). - The surface \(\Sigma\) can be taken as the planar disk \(x^2 + y^2 \leq 1\) at \(z = 1\). Below is the detailed solution to guide you through each step. ---
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