ise Simpson's rule and trapezoidal method to find the volume of cut and fill of theattached table. Road width is 10 m and side stope is 2:1.Sta5 m10 m5 m2.06F 1.210 m1+00F 2.062.062.062.061+501.151.151.151.252+002+503+00F 1.56F 2.94с 0.97C 0.47C 1.270.921.03C 0.82C 0.3с 1.54C 0.95F 2.30.140.630.911.021.021.623+502.042.214+002.452.782.943.04

Answered: Image /qna-images/answer/0de8efd9-9f4c-4d9d-8991-38dfc6971de7.jpg

Use Simpson's rule and trapezoidal method to find the volume of cut and fill of the attached table. Road width is 10 m and side slope is 2:1.2 Sta 5 m 5 m 10 m F 2.06 10 m 1+00 1+50 2.06 2.06 2.06 F 1.2 2.06 1.15 1.15 1.15 1.25 F 1.56 F 2.94 с 0.97 C 0.47 с 1.27 с 1.54 C 0.95 F 2.3 C 0.82 C 0.3 2+00 0.92 2+50 1.03 0.14 3+00 0.63 0.91 1.02 3+50 1.02 1.62 2.04 2.21 4+00 2.45 2.78 2.94 3.04

Use Simpson's rule and trapezoidal method to find the volume of cut and fill of the attached table. Road width is 10 m and side slope is 2:1.2 Sta 5 m 5 m 10 m F 2.06 10 m 1+00 1+50 2.06 2.06 2.06 F 1.2 2.06 1.15 1.15 1.15 1.25 F 1.56 F 2.94 с 0.97 C 0.47 с 1.27 с 1.54 C 0.95 F 2.3 C 0.82 C 0.3 2+00 0.92 2+50 1.03 0.14 3+00 0.63 0.91 1.02 3+50 1.02 1.62 2.04 2.21 4+00 2.45 2.78 2.94 3.04

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Find the slope and deformed functions of the system in the figure p(x)=H(x/l):
1. Complete the differential level notes shown below and perform the customary arithmetic check. BS HI FS ELEVATION STA 2.085 ВМ 10 ТР 1 2.015 0.982 TP 2 1.864 1.428 0.579 1.527 ТР 3 ВМ 11 0.423 2.423 TP 4 1.446 1.807 ТР 5 ТР 6 1.778 1.725 2.051 2.339
help me asap pls :((
A beam is shown in the figure below, and the flexural stiffness of the beam section is constant EI: Use the conjugate beam method (Conjugate Beam Method) to obtain the slope (Slope) after the deformation of point A and the vertical displacement (Deflection) of point C *The correct answer is 24 kN-m2/EI clockwise and 58.7 kN-m3 /EI down, but I need to calculate steps, thanks
2. During the measurement at the sides of the slope, the data was recorded into three bays, the following information (Table 1.0) was obtained: Table 1.0 Difference in Tension (N) Temperature (°C) Bay Measured Length (m) level between end (m) 1 25.842 19 +0.285 150 27.365 18 -0.236 120 3 21.645 21 -0.239 160 The 30 meter tape used has a mass of 0.400 N/m and a cross-sectional area of 3.00 mm?. It was standardised on the flat at 20 °C under a pull of 100 N, the actual length was 29.995 m during the measuring works. The coefficient of linear expension for the materials of the tape us 0.000015 / °C and Young's Modulus is 20.5 x 104 MN/m?. Calculate the absolute length of survey line in 3 decimal point. Slope correction = -v² 2s Sagging correction = - w²L³ 24P? Tension correction = (P – Ps) EL AE Temperature correction = a (T-Ts) (L)
show solutions b) Spacing of stirrups at 1.0m from fos.
Use wedge method to analysis the stability of slope shown below. Use wedges A and B drawn in the figure. Redo the calculations in case the water table exist at the top level of slope that shown in the figure of the previous example. 161.9 m Y- 21 ANim Core - 35 60m Interface characteristic 4110 ANm 150 (a) 109 5 m 23 -=23 f--- -85m tan d tan FS 39.9m 42.4 m 223 m FS Tnsm P, tan d 176 m FS 73,4 m 100.0 m (b) (c) (d)
Determine the lengths of 2 sides (a and b) and area of an oblique triangle. You must provide solutions to support your answer: Given: A = 53° 28' 15" Formula a² = b² +c²-2bc cos A B = 29° 31' 45" Area = ab Sin C Side c = 3627.58 ft a / Sin A = b / Sin B = c/ Sin C
Utilice el método del trabajo virtual para determinar la deflexión horizontal en el punto A y la de flexión vertical en el punto B en el marco mostrado. I= .0005040 m^4 E=200 Gpa.
ASAP please help now. Be careful on the gven. Round off to 3 decimal places. I will give thumbs up. Thank you!
Please solve using MOUC (Method of Undetermined Coefficients)
: Check the slab thickness for deflection control if slab thickness = 170 mm and the values of flexural stiffness (a) as shown on the beams in the figure below. fc = 21 MPa, fy = 420 MPa and Cols. = (375*375) mm. 7.6m 7.6m 18:57 1257 B 1. 3792 3.79 89 89 3 379 +379 89 89 7.6m - 6m 6m 6m