Use sigma notation to write the sum. 1 1 9 (1) 9(3) 14 i = 1 + 1 9(2) + X ++ 1 9(14)

Q: 7 Evaluate the sum i(3i + 2) i=1

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Q: Evaluate the sum 8 Σk(2k +3) = k=1 Σκ(2k + 3). k = 1 (Simplify your answer.)

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Q: Use sigma notation to write the sum. 8 8n 8n Σ i= 1

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Q: -3 – 12 – 21... –192|

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Q: Evaluate the sum Σ ( - 16k). S k=1

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Q: Write the sum using sigma notation: 6 +9 + 12 + 15 +…+ 42 = B, where n=1 A - B- %3D

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Q: 1-5+25-125. Write using summation notation

A: It is given that,         1-5+25-125. we have write it into summation notation

Q: Write the sum without using sigma notation. n Σ(-1)² + 2x³² j = 1

A: Summation means  Putting j=1,2,3.......n

Q: 6. Consider 8+16 + 24 +...+160 + 168. (a) Rewrite the sum in sigma notation. (b) Find the sum.

A: First I have find the number of terms in the given series and then write it in summation form , then…

Q: Evaluate the summation: 1(11)+2(2!)+3(3!)+...+t(t!); t=3

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Q: και Σ(+1-143) (b) Evaluate the sum i=1

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Q: Use sigma notation to write the sum. 1 5(4) Σ i = 1 + 2 5(5) + 3 5(6) + + 10 5(13)

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Q: Use sigma notation to write the sum. X Σ* [[ IM [²(²¹) + ¹] + [²( ² ) + ³] + - + [² (¹) + ¹] [2 [2…

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Q: Let Sn = n Σ k-1 √k Estimate how many terms are required before sn ≥ 100.

A: We shall be using basic inequalities to solve this problem.

Q: 1. 34 Calculate the sum k-4 (k – 1)!

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Q: Rewrite the summation by separating off the final term. n+1 Σ m(m + 1) = m = 1 ??? V m = 1 m(m + 1)…

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Q: 12 E (k + 2)(k + 5) k=1

A: Evaluate the sum    ∑k=112k+2k+5

Q: Evaluate the sum k(4k+5). 9 9 Σk(4k+5) = k=1 (Simplify your answer.)

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Q: Evaluate the summation i=1 28 10 30

A: Given summation is ∑i=13i3-i. Evaluate the value of the given summation ∑i=13i3-i. Formula used: 1)…

Q: 1 1+ 4 1 9

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Q: Use sigma notation to write the sum. 61 3 1 3 + 2 3 + 3 3 12 12 6 6.

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