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Evaluate the sum k(4k+5). 9 9 Σk(4k+5) = k=1 (Simplify your answer.)

Evaluate the sum k(4k+5). 9 9 Σk(4k+5) = k=1 (Simplify your answer.)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Evaluate the Sum** Evaluate the sum from \( k = 1 \) to \( k = 9 \) of \( k(4k + 5) \). \[ \sum_{k=1}^{9} k(4k + 5) \] \[ \sum_{k=1}^{9} k(4k + 5) = \, \_\_ \, \text{(Simplify your answer.)} \] Instructions: Compute the value of the sum by substituting each integer value of \( k \) from 1 to 9 into the expression \( k(4k + 5) \), then add all the results together. Simplify your final answer.
Transcribed Image Text:**Evaluate the Sum** Evaluate the sum from \( k = 1 \) to \( k = 9 \) of \( k(4k + 5) \). \[ \sum_{k=1}^{9} k(4k + 5) \] \[ \sum_{k=1}^{9} k(4k + 5) = \, \_\_ \, \text{(Simplify your answer.)} \] Instructions: Compute the value of the sum by substituting each integer value of \( k \) from 1 to 9 into the expression \( k(4k + 5) \), then add all the results together. Simplify your final answer.
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