Use sigma notation to write the following Riemann sum. Then, evaluate the Riemann sum using formulas for the sums of powers of positive integers or a calculator. The right Riemann sum for f(x) = x + 6 on [0,4] with n = 30. Write the right Riemann sum. Choose the correct answer below. 30 2 2 Ο Α. Σ -k-6 15 k= 1 15 30 2 -k -6 OB. k= 1 30 2 OC. Σ -k +6 15 15 k= 1 30 2 <+ 15 15 k= 1 D.
Use sigma notation to write the following Riemann sum. Then, evaluate the Riemann sum using formulas for the sums of powers of positive integers or a calculator. The right Riemann sum for f(x) = x + 6 on [0,4] with n = 30. Write the right Riemann sum. Choose the correct answer below. 30 2 2 Ο Α. Σ -k-6 15 k= 1 15 30 2 -k -6 OB. k= 1 30 2 OC. Σ -k +6 15 15 k= 1 30 2 <+ 15 15 k= 1 D.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Use sigma notation to write the following Riemann sum. Then, evaluate the Riemann sum using formulas for the sums of powers of positive integers or a calculator.
The right Riemann sum for
f(x)=x+6 on [0,4] with n=30.
![Use sigma notation to write the following Riemann sum. Then, evaluate the Riemann sum using formulas for the sums of powers of positive integers or a calculator.
The right Riemann sum for f(x) =x +6 on [0,4] with n= 30.
Write the right Riemann sum. Choose the correct answer below.
30
2
k -6
15
2
O A. E
15
k= 1
30
O B. E
2
-k -6
15
k= 1
30
-k + 6
15
15
k= 1
30
2
2
OD. E 15k* 15
k=1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F277d8e9e-796c-4923-a9a2-4c05d5ad95df%2Ff871f038-7e39-4aed-a633-954ad0f6319e%2Fe50aswx_processed.png&w=3840&q=75)
Transcribed Image Text:Use sigma notation to write the following Riemann sum. Then, evaluate the Riemann sum using formulas for the sums of powers of positive integers or a calculator.
The right Riemann sum for f(x) =x +6 on [0,4] with n= 30.
Write the right Riemann sum. Choose the correct answer below.
30
2
k -6
15
2
O A. E
15
k= 1
30
O B. E
2
-k -6
15
k= 1
30
-k + 6
15
15
k= 1
30
2
2
OD. E 15k* 15
k=1
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