use Series to find He integred x 2 Find the Sum of the Series

Q: Express the series as a rational function.

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Q: Find the sum of the terms of a series 2n-1 2"

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Q: Find the sums of the series

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Q: 10 n(n +2) n=1

A: We have to find the sum

Q: Find the sum of the series: (- 1)"4" 3 (2n + 1)!

A: We know sin x = ∑n=0∞(-1)n x2n+1(2n+1)! Putting x=2, we get sin 2 = ∑n=0∞(-1)n 22n+1(2n+1)!

Q: А. Σ 5n –1 n=1

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Q: Find the sum of the series.

A: After separating both terms, the series becomes infinite geometric series.

Q: use series t Find 2-4 x 2.

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Q: > 3n+14-n n=1

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Q: 3 (4 3 (4 Σ 4 k=1 7 9.

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Q: E1 (arctan(2n+1) – arctan(2n – 1)) n=1

A: The given series is: ∑n=1∞tan-1(2n+1)-tan-1(2n-1)

Q: Find the sum of the series

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Q: 2 En=1 n(n+1)

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Q: 7 + 10 + 13 + . + 40 i-

A: 7+10+13+....+40  First term⇒ a1=7, Last term⇒ an=40common differnce⇒10-7=3 Last term=First…

Q: α 4" n=2 5n!

A:

Q: find the series of cosx4 and (cosx)4

A: The series for cosx is cosx=1-x22!+x44!-x66!+...

Q: 7+7+77+ 49 + to 12 terms

A: We need to find the sum of the series 7+7+77+49+... 12 terms. So,                  7+7+77+49+... 12…

Q: express (12+x)ln⁡(12+x) as a power series

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Q: Find the sum of the series

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Q: (x + 2) E nan(x + 2)"- – E nan (x + 2)" n=3 n=1

A: First make summation initial point same by shifting then merge the terms as in next step.

Q: find the sum of the series

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Q: SET-UP a triple integral that will solve for volume of the solid S bounded by the sphere x² + y²…

A: Volume =∭dzdxdyAccording to the given surfacesx2+y2+z2=4⇒z is from -4-x2-y2 to +4-x2-y2x2+y2=1⇒ x is…

Q: Find the sum of n terms of the series whose nth term is (i) 2n? - 3n + 5 (ii)n? + 2"

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Q: Find the sum of the series.

A: The series is:

Q: Oppgave 8 Finn summen av rekken uttrykt som en funksjon. 1 1 1 2².2 23.3 24.4 1 2 n=1 1 21 n

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Q: g(t) = 3 – 2t, 0<t<n %3D

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Q: Find the exact sum of the series.

A: We will use the two numbers of each denominator to rewrite the numerators. Notice that difference…

Q: Find the sums of the series

A: Given series : ∑n=0∞ e-n The given series is ∑n=0∞ e-n=e0+e-1+e-2+e-3+.....∑n=0∞…