Use part I of the Fundamental Theorem of Calculus to find the derivative of f(2) = | V+ 2*dt 2 f' (2) = [NOTE: Enter a function as your answer. Make sure that your syntax is correct, i.e. remember to put all the necessary (, ), etc. ]

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
Topic Video
Question
100%
---
### Calculus Tutorial: Using the Fundamental Theorem of Calculus

#### Application of the Fundamental Theorem of Calculus - Part I

In this exercise, we will use Part I of the Fundamental Theorem of Calculus to find the derivative of the given function.

\[ f(x) = \int_{-2}^{x} \sqrt{t^3 + 2^3} \, dt \]

We aim to determine \( f'(x) \).

---

\[ f'(x) = \boxed{\text{Enter a function as your answer. Make sure that your syntax is correct, i.e. remember to put all the necessary } ( \text{ , } ) \text{ , etc.}} \]

[NOTE: Enter a function as your answer. Make sure that your syntax is correct, i.e., remember to put all the necessary parentheses, commas, etc.]

---

In this problem, the notation provided involves an integral with variable limits of integration, specifically from -2 to x. The Fundamental Theorem of Calculus Part I tells us that if \( F(x) \) is an antiderivative of \( f(x) \), then:
\[ \frac{d}{dx} \left( \int_{a}^{x} f(t) \, dt \right) = f(x) \]

In this context, the integrand \( \sqrt{t^3 + 8} \) is a function of \( t \). Thus, applying the theorem, we find that:

\[ f'(x) = \sqrt{x^3 + 8} \]

This result leverages the property that taking the derivative of the integral with respect to its upper limit \( x \) effectively "evaluates" the integrand at its upper limit.

### Summary

By employing the Fundamental Theorem of Calculus Part I, we transformed our integral expression into a derivative, thereby simplifying our function to its derivative form.

For further practice, ensure your syntax is correct when inputting mathematical expressions, always considering proper use of parentheses and other notation.
Transcribed Image Text:--- ### Calculus Tutorial: Using the Fundamental Theorem of Calculus #### Application of the Fundamental Theorem of Calculus - Part I In this exercise, we will use Part I of the Fundamental Theorem of Calculus to find the derivative of the given function. \[ f(x) = \int_{-2}^{x} \sqrt{t^3 + 2^3} \, dt \] We aim to determine \( f'(x) \). --- \[ f'(x) = \boxed{\text{Enter a function as your answer. Make sure that your syntax is correct, i.e. remember to put all the necessary } ( \text{ , } ) \text{ , etc.}} \] [NOTE: Enter a function as your answer. Make sure that your syntax is correct, i.e., remember to put all the necessary parentheses, commas, etc.] --- In this problem, the notation provided involves an integral with variable limits of integration, specifically from -2 to x. The Fundamental Theorem of Calculus Part I tells us that if \( F(x) \) is an antiderivative of \( f(x) \), then: \[ \frac{d}{dx} \left( \int_{a}^{x} f(t) \, dt \right) = f(x) \] In this context, the integrand \( \sqrt{t^3 + 8} \) is a function of \( t \). Thus, applying the theorem, we find that: \[ f'(x) = \sqrt{x^3 + 8} \] This result leverages the property that taking the derivative of the integral with respect to its upper limit \( x \) effectively "evaluates" the integrand at its upper limit. ### Summary By employing the Fundamental Theorem of Calculus Part I, we transformed our integral expression into a derivative, thereby simplifying our function to its derivative form. For further practice, ensure your syntax is correct when inputting mathematical expressions, always considering proper use of parentheses and other notation.
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Chain Rule
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning