Use nested for loops to solve this problem. Your encode function only needs to display the string. A Only two functions, print and range may be used to solve this problem. Lists, dictionaries, etc. are not needed. Write a function called encode that receives two parameters: a string to encode and an integer for the number of rows. The string should then be split across multiple rows and displayed in a new order. For instance, the string abcdefghijklmnopqrstuvwxyz should be encoded as: row 1: a e im quy row 2: b fjnrv z row 3: c g kos w row 4: d h 1ptx which results in, reading across from left to right: aeimquybfjnrvzcgkoswdhlptx. Hint Can you devise a nested for loop to print the following output (assuming rows = 4)? 0 4 8 12 15 9 13 2610 14 37 11 15 If so, how do those numbers relate to the index and desired output of the encode function? Recall, you can print a character without a newline being automatically appended with print(value, end-""). Sample Outputs • encode("hey we are almost done!", 3) - outputs →h elsdeewa mto!yerao n encode ("0123456789", 4) outputs 0481592637 • encode("abcdefghijklmnopqrstuvwxyz". 4) outputs aeimquybfjnrvzcgkoswdhlptx

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