Use mathematical induction to prove the formula for all integers n ≥ 1. 1+ 4 + 7 + 10 + ... + (3n - 2) = (3-1) 2 Let S be the equation 1 +4+7+ 10 ++ (3n - 2) = (3n - 1). We will show that S is true for every integer n 2 1. n Select S, from the choices below. O 1+4= 5(2-1) = (3-1-1) 01+4=(3-3+ 1=(3-1-1) 2 = 1) Nice job! The selected statement is true because both sides of the equation equal Show that for each integer k ≥ 1, if Sk is true, then Sk + 1 is true. Assuming S is true, we have the following. (Simplify your answers completely.) Sk = 1+4+7+ 10 + ... + Then we have the following. (Simplify your answers completely.) 2)+(²([ 3 Sk+1=1+4+7+ 10 ++ (3k − 2) + = Sk + = - (3k-1) + +1)(1 (k+ 1) 2 k + 1 2 1)-¹) Hence, Sk + 1 is true, which completes the inductive step and the proof by mathematical induction

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