Fill in the blanks in the proof of the of fact that 3" – 1 is a multiple of 2 for every natural n. "Base case: if k= [ Select] , then 31 – 1= 2 is a multiple of 2, as needed. Induction step: Assume that for [ Select ] natural k, 3k – 1 is a multiple of 2. Consider n= [ Select] . Then 3k+1 – 1 = 3k . 3 –1= 3*(2+1) – 1 = 3* . 2 – (3* – 1). Notice that the first term is a multiple of 2 and the second term is a multiple of 2 by induction assumption. Therefore, 3k+1 – 1 is a multiple of 2, as required. The proof is complete. " >

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