Use linear approximation, i.e. the tangent line, to approximate ✓125.1 as follows: Let f(x) = = V. The equation of the tangent line to f(x) at x = 125 can be written in the form y = mx + b where m is: and where b is: Using this, we find our approximation for ✓125.1 is

Q: X a) y = x²-1 x-1

A:

Q: Let A be an m x n matrix, and let B and C have sizes for which the indicated sums and products are…

A: If the product AB is defined, the entry in row i and column j of AB is the sum of the products of…

Q: A solid concrete porch consists of 3 steps and a landing. The steps have a tread of 11 inches, a…

A:

Q: and equations for the tangent plane and the normal line at point Po (X-Yo Zo) (1.5,0) on the surface…

A:

Q: Find an equation for the line tangent to the following curve at the point (2, 1). 1 – y = sin (x + y…

A:

Q: Find an equation of the tangent line to the graph of the function at the given point. y = 4 – x² –…

A:

Q: The qAth derivative fx)= (x

A:

Q: Let f(x) : x4 Find all values of I such that the slope of the tangent line is - -4.

A: The given function is fx=1x4 and the slope of the tangent line is -4.