Answered: Use Kepler's third law, as modified by…

Science

Physics

Use Kepler's third law, as modified by Newton, to calculate the mass of the Earth and Moon in units of the Sun's mass

The Solar System

9th Edition

ISBN:9781305804562

Author:Seeds

Publisher:Seeds

Chapter5: Gravity

Section: Chapter Questions

Problem 11P

See similar textbooks

Related questions

Q: Calculate the Earth's mass given the acceleration due to gravity at the North Pole is 9.830 m/s2 and…

A: Gravitational acceleration of Earth is,

Q: The mass of Mars is 6.42 × 10^23 kg. Its moon Phobos is 9.378 x 10^6 meters away from Mars, with a…

A: Given: mass of mars (Mm) = 6.42*1023kg mass of phobos (Mp) = 1.06*1016kg Distance between…

Q: The mass of the Sun is 1.99 × 10^30 kg. Jupiter is 7.79 × 10^8 km away from the Sun and has a mass…

Q: A person with a mass of 27 kg is standing on a planet and experiences a weight of XYZ N. If the…

Q: The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force…

A: Given that: Mass of sun, Ms = 1.99X 1030 kg Mass of earth,Me = 5.98 X 1024 Kg Mass of moon, Mm=…

Q: A ball of mass m is found to have a weight Wx on Planet X. Which of the following is a correct…

A: The weight of an object in a planet is the gravitational force exerted by the planet on it. It is…

Q: Cavendish determined that the gravitational constant was equal to 6.67x10-11 N m2/kg2. The Earth's…

A: Given data: Universal gravitational constant (G) = 6.67×10-11 Nm2/kg2 Earth's radius (R) = 6.37×106…

Q: A 4.4 kg mass weighs 35.64 N on the surface of a planet similar to Earth. The radius of this planet…

A: Weight on body of mass m=mg where g=acceleration due to gravity on surface of planet According to…

Q: Newton’s version of Kepler’s third law is P2 = 4 π2 / [G (M1 + M2)] · a3, where G is the…

A: From Newton’s version of Kepler’s third law

Q: According to Lunar Laser Ranging experiments the average distance L M from the Earth to the Moon is…

Q: Scientists have discovered a distant planet with a mass of 8.4x1023 kg. The planet has a small moon…

A: The period of the satellite in seconds is, T=5×3600 s+13×60 s=18780 s The equation for the period of…

Q: Newton's Law of Gravitation says that the magnitude F of the force exerted by a body of mass m on a…

Q: The mass of Mars is 6.42 × 10^23 kg. Its moon Phobos is 9.378 x 10^6 meters away from Mars, with a…

Q: The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an…

Q: A moon is orbiting its planet in UCM. If the planet has a mass of 2.6 x 1026kg and the moon is…

A: Given data: The moon have uniform circular motion Mass of planet (M) = 2.6×1026 kg Speed (v) =…

Q: Find the magnitude of the gravitational force (in N) between a planet with mass 6.75 * 10 ^ 24 * kg…

A: Mass of the planet ( MP) = 6.75 * 10 24 kg Mass of the moon ( MM ) = 2.55 * 10 22 kg Average…

Q: Newton's Law of Gravitation says that the magnitude F of the force exerted by a body of massm on a…

A: The newton's law of gravitation is, F=GmMr2 (1) Then the derivative of F dF/dr is, dFdr=d…

Q: A newly discovered planet has four times the mass of the Earth, but a person's weight on the new…

A: Let the mass of Earth be ME.The mass of the new planet will then be Mp = 4MELet the radius of the…

Q: The gravitational force between two people is found to be 5.9 x 10-11 N. What would the…

Q: Newton's theory of gravity, together with the Cavendish experiment to measure the value of Newton's…

A: mass = M = 1.989 X 1030 Kg radius = R = 6.96 X 108 m

Q: The orbit of Earth’s moon has a period of 27.3 days and a radius (semi-major axis) of 2.57 ×10-3…

A: Given data: T=27.3 daysr=3.85×105 km Need to determine the mass of Earth.

Q: An object with a mass of 27 kg is standing on a planet and experiences a weight of 273 N. If the…

A: The force on the person standing on the planet is given by, F=GMmR2where,G=gravitational constant…

Q: Newton’s version of Kepler’s third law is P2 = 4 π2 / [G (M1 + M2)] · a3, where G is the…

A: Given data: The value of gravitational constant G is 6.67×10-11 m3/kg.s2 The average distance is…

Q: he gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an…

Q: Scientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the…

A: The expression for the radius from the escape velocity relation is: r=2Gmmarsv2 Here, v is the speed…

Q: The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force…

A: We observe gravity everywhere, we can feel it very slightly. Gravity is a weak force, but still, it…

Q: According to Lunar Laser Ranging experiment the average distance LM from the Earth to the Moon is…

A: 1) Average distance between Earth and Moon is given as: LM = 3.92 × 105 km= 3.92× 108 m 2) Time…

Q: A new planet named Vulcan has been discovered. Vulcan is a rather large planet with a radius twice…

Q: The gravitational acceleration constant gx on Planet X can be approximated by determining the…

A: Given data: The acceleration due to gravity on the planet gx = 3.8 m/s2 Universal gravitational…

Q: Scientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the…

A: 1. The force of attraction between Mars and the satellite is…

Q: A ball of mass m is found to have a weight Wx on Planet X. Which of the following is a correct…

A: Gravitational field strength is g=Fgm=WXm

Q: .) Which of the following quantities would change the speed the satellite needs to orbit at? a.)the…

A: Orbital velocity V0=GM/r r= R+H M= Mass of Mars GIVEN mmars = 6.4191 x 1023 kgrmars…

Q: Which of the following statements cannot be supported by Kepler's laws of planetary motion? a The…

Q: Mars’s moon Phobos orbits the planet at a distance of 9380 km from its center, and it takes 7 hours…

A: It is given that, r=9380 km=9380×103 mt=7 hr 39 min=27540 s

Q: One of Saturn's moons is named Mimas. The mean orbital distance of Mimas is 1.87 x 108 m. The mean…

A: The period of a satellite and its mean distance from the central body is related by the equation,

Q: A 66kg student travels to Mars! You may enter answers in scientific notation as shown: 1.23 x 105 =…

A: The weight of the student in earth is as follows: Wearth=mgWearth=60 kg9.8 m/s2Wearth=588 N…

Question

Use Kepler's third law, as modified by Newton, to calculate the mass of the Earth and Moon in units of the Sun's mass.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1 - Analyzing the Question

VIEW

Step 2 - Solving the Question

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Let gM represent the difference in the gravitational fields produced by the Moon at the points on the Earths surface nearest to and farthest from the Moon. Find the fraction gM/g, where g is the Earths gravitational field. (This difference is responsible for the occurrence of the lunar tides on the Earth.)
Calculate the mass of the Sun based on data for average Earth’s orbit and compare the value obtained with the Sun’s commonly listed value of 1.9891030kg .
In the law of universal gravitation, Newton assumed that the force was proportional to the product of the two masses (m1m2) . While all scientific conjectures must be experimentally verified, can you provided arguments as to why this must be? (You may wish to consider simple examples in which any other form would lead to contradictory results.)
If a planet with 1.5 times the mass of Earth was traveling in Earth’s orbit, what would its period be?
Calculate the effective gravitational field vector g at Earths surface at the poles and the equator. Take account of the difference in the equatorial (6378 km) and polar (6357 km) radius as well as the centrifugal force. How well does the result agree with the difference calculated with the result g = 9.780356[1 + 0.0052885 sin 2 0.0000059 sin2(2)]m/s2 where is the latitude?
The Scope and Scale of Physics Find the order of magnitude of the following physical quantities. (a) The mass of Earth’s atmosphere: 5.11018kg : (b) The mass of the Moon’s atmosphere: 25,000kg ; (c) The mass of Earth’s hydrosphere: 1.41021kg : (d) The mass of Earth: 5.971024kg : (e) The mass of the Moon: 7.341022kg : (f) The Earth-Moon distance (semimajor axis): 3.84108m : (g) The mean Earth-Sun distance: 1.51011m : (h) The equatorial radius of Earth: 6.38106m : (i) The mass of an electron: 9.111031kg : (j) The mass of a proton: 1.671027kg : (k) The mass of the Sun: 1.991030kg .
A newly discovered planet has four times the mass of the Earth, but a person's weight on the new planet's surface is the same as the person's weight on the Earth's surface. The radius of the new planet in terms of the radius R of Earth is
One of Saturn's moons is named Mimas. The mean orbital distance of Mimas is 1.87 x 108 m. The mean orbital period of Mimas is approximately 23 hours (8.28x104 s). Use this information to estimate a mass for the planet Saturn.
Newton’s version of Kepler’s third law is P2 = 4 π2 / [G (M1 + M2)] · a3, where G is the gravitational constant, which is equal to 6.67*10-11 m3 kg-1 s-2. NASA's New Horizons mission found that Pluto's moon Charon orbits Pluto every 5.7 days at an average distance of 19200.0 km. What is the combined mass (in kg) of Pluto and Charon?
According to Lunar Laser Ranging experiments the average distance L M from the Earth to the Moon is approximately 3.85 X 105 km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). Calculate the mass of the Earth and provide your answer in units of 1024 kg. For example, if your answer is 2.7×1024 enter 2.7.
The gravitational force between two people is found to be 5.9 x 10-11 N. What would the gravitational force be between the two people if person A's mass is decreased to 1/3 the original value, person B's mass is increased to 3/2 of the original mass, and the separation distance between them is increased by a factor of 2? Expressed in scientific notation, is a.b x 10 cd N. The values for a, b, c, and d are J 1 E X $ 4 R C C F5 de Lo % 5 a DA F6 6 T Y ✈ ? & 7 U F8 * 1 8 F9 2 F10 ( 93 O and F11 ) 0 1/4 § P F12 PrtSc Impr. Écr. 1/2 + 11 Insert Ins = 3/4 [[A Delete Suppr. 11>
Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10^24 kg, the mass of Jupiter is 1.9 x 10^27 kg and when closest, the average distance is about 5.88 x 10^11 m. Use scientific notation for final result. Use G= 6.7 x 10^-11 N-m^2/kg^2.