Use induction to prove: for any integer n > 1, 3|(n – 4n + 6). Hint: this question is case sensitive, you should ONLY use k, but not K in your answers. Base case n = ,n? - 4n + 6 = which is divisible by 3. Inductive step Assume that for any k > , 3| , we will prove that 3| By the inductive hypothesis, there exists an integer m such that = 3m. It follows that k3 %3D (k + 1)3 – 4(k + 1) + 6 = k³+ k2+ k+

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