Use Hess's law and the following data to calculate the standard enthalpy of formation of ethanol, CH3CH2OH(f). CH,CH,ОН()+ 3 0-(g) — 2 CO,(g) + 3 H,0(e) AHn = -1368.2 kJ/mol rxn C(s) + O2(g) → CO(g) ΔΗ- -393.5 kJ/mol H;(g) + } O,(g)→ H,O(t) ΔΗ AH; = -285.9 kJ/mol

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**Calculation of the Standard Enthalpy of Formation for Ethanol Using Hess’s Law**

To calculate the standard enthalpy of formation of ethanol, \( \text{CH}_3\text{CH}_2\text{OH}(l) \), utilize Hess's law and the given reaction data.

**Given Reactions and Their Enthalpies:**

1. \( \text{CH}_3\text{CH}_2\text{OH}(l) + 3 \, \text{O}_2(g) \rightarrow 2 \, \text{CO}_2(g) + 3 \, \text{H}_2\text{O}(l) \)
   - \( \Delta H^\circ_{\text{rxn}} = -1368.2 \, \text{kJ/mol} \)

2. \( \text{C}(s) + \text{O}_2(g) \rightarrow \text{CO}_2(g) \)
   - \( \Delta H^\circ_f = -393.5 \, \text{kJ/mol} \)

3. \( \text{H}_2(g) + \frac{1}{2} \, \text{O}_2(g) \rightarrow \text{H}_2\text{O}(l) \)
   - \( \Delta H^\circ_f = -285.9 \, \text{kJ/mol} \)

These thermochemical equations and their associated enthalpies enable the calculation of the standard enthalpy of formation for ethanol through a series of transformations, as described by Hess’s law. This law states that the total enthalpy change for a reaction is the same, regardless of the route taken, provided the initial and final conditions are the same.
Transcribed Image Text:**Calculation of the Standard Enthalpy of Formation for Ethanol Using Hess’s Law** To calculate the standard enthalpy of formation of ethanol, \( \text{CH}_3\text{CH}_2\text{OH}(l) \), utilize Hess's law and the given reaction data. **Given Reactions and Their Enthalpies:** 1. \( \text{CH}_3\text{CH}_2\text{OH}(l) + 3 \, \text{O}_2(g) \rightarrow 2 \, \text{CO}_2(g) + 3 \, \text{H}_2\text{O}(l) \) - \( \Delta H^\circ_{\text{rxn}} = -1368.2 \, \text{kJ/mol} \) 2. \( \text{C}(s) + \text{O}_2(g) \rightarrow \text{CO}_2(g) \) - \( \Delta H^\circ_f = -393.5 \, \text{kJ/mol} \) 3. \( \text{H}_2(g) + \frac{1}{2} \, \text{O}_2(g) \rightarrow \text{H}_2\text{O}(l) \) - \( \Delta H^\circ_f = -285.9 \, \text{kJ/mol} \) These thermochemical equations and their associated enthalpies enable the calculation of the standard enthalpy of formation for ethanol through a series of transformations, as described by Hess’s law. This law states that the total enthalpy change for a reaction is the same, regardless of the route taken, provided the initial and final conditions are the same.
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