Use geometry (not Riemann sums) to evaluate the definite integral. Sketch the graph of the integrand, show the region in question, and interpret your result. xp X- 6 The integrand is f(x) = /49-x². Graph the integrand. The correct graph is shown below. The area equivalent to the value of the definite integral is the area of the region bounded by the graph, the x-axis, and the lines 2=x pue 0 = X Graph the region in question. The correct graph is shown below. The region is one-fourth of a circle. The area of a circle is equal to xr", where r is the radius of the circle. The radius of the circle L=J S! The area of the region is The net area of the region is 7. Thus, 49-x dx =

Use geometry (not Riemann sums) to evaluate the definite integral. Sketch the graph of the integrand, show the region in question, and interpret your result. xp X- 6 The integrand is f(x) = /49-x². Graph the integrand. The correct graph is shown below. The area equivalent to the value of the definite integral is the area of the region bounded by the graph, the x-axis, and the lines 2=x pue 0 = X Graph the region in question. The correct graph is shown below. The region is one-fourth of a circle. The area of a circle is equal to xr", where r is the radius of the circle. The radius of the circle L=J S! The area of the region is The net area of the region is 7. Thus, 49-x dx =

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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