Use Gauss' law to find the electric field E at a distance R from a point charge +q located at the origin (0,0,0).
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A: N/C = (J/m)/C = J / (m x C) = (J/C)/m = V/m
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A: Given Data: a=0.84 mb=0.92 mq1=+3.7 μCq2=-2.6 μC Standard Data: 14πεo=9×109 N·m2·C-2
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- Two charges are located in the x-y plane. If q1 -3.50 nC and is located at (x = 0.00 m, y = 0.960 m), and the second charge has magnitude of q2 = 4.80 nC and is located at (x = 1.40 m, y 0.650 m), calculate the x and y components, Ex and Ey, of the electric field, É, in component form at the origin, (0, 0). The Coulomb force constant is 1/ (4reo) = 8.99 x 10° N · m²/C². -13.58 -40.45 Ex N/C Ey N/C Incorrect Incorrect IIAn electric dipole consists of two charges, +4 μC and -4 μC, separated by a distance of 2 cm. Determine the electric field strength at a point on the axial line of the dipole, 4 cm away from its center.