a disk of radius R = 2.79 cm having a uniformly distributed charge of +4.98 μC. (a) Using the expression above, compute the electric field at a point on the axis and 3.27 mm from the center. N/C (b) Explain how the answer to part (a) compares with the field computed from the near-field approximation E = 0/2€0¹

a disk of radius R = 2.79 cm having a uniformly distributed charge of +4.98 μC. (a) Using the expression above, compute the electric field at a point on the axis and 3.27 mm from the center. N/C (b) Explain how the answer to part (a) compares with the field computed from the near-field approximation E = 0/2€0¹

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

The total electric field at a point on the axis of a uniformly charged disk, which has a radius R and a uniform charge density of o, is given by the following expression, where x is the distance of the point from the disk.
E = 2tk c
60 [1 - (R² + X²)1/72]
Consider a disk of radius R = 2.79 cm having a uniformly distributed charge of +4.98 µC.
(a) Using the expression above, compute the electric field at a point on the axis and 3.27 mm from the center.
N/C
(b) Explain how the answer to part (a) compares with the field computed from the near-field approximation E = 0/2€-

(c) Using the first expression above, compute the electric field at a point on the axis and 32.7 cm from the center of the disk.
N/C
(d) Explain how the answer to part (c) compares with the electric field obtained by treating the disk as a +4.98-C charged particle at a distance of 32.7 cm.

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